【项目3-分数类中的运算符重载】

　　（1）实现分数类中的运算符重载，在分数类中可以完成分数的加减乘除（运算后再化简）、比较（6种关系）的运算。可以在第4周分数类代码的基础上开始工作。

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1. class CFraction
2. {
3. private:
4. int nume;  // 分子
5. int deno;  // 分母
6. public:
7. //构造函数及运算符重载的函数声明
8. };
9. //重载函数的实现及用于测试的main()函数

/*
*Copyright (c)2014,烟台大学计算机与控制工程学院
*All rights reserved.
*dood luck
*文件名称：d.cpp
*作    者：张旺华
*完成日期：2015年5月7日
*版 本 号：v1.0
*
*/
#include <iostream>
using namespace std;
class CFraction
{
private:
    int nume;  // 分子
    int deno;  // 分母
public:
    //构造函数及运算符重载的函数声明
    CFraction(int n=1,int d=1);
    void setCFraction(int n,int d);
    void display();
    friend CFraction change(CFraction &c);
    CFraction operator+(CFraction &c);
    CFraction operator-(CFraction &c);
    CFraction operator*(CFraction &c);
    CFraction operator/(CFraction &c);
    bool operator > (CFraction &t);
    bool operator < (CFraction &t);
    bool operator >= (CFraction &t);
    bool operator <= (CFraction &t);
    bool operator == (CFraction &t);
    bool operator != (CFraction &t);
    //赋值运算符的重载
    CFraction operator+=(CFraction &c);
    CFraction operator-=(CFraction &c);
    CFraction operator*=(CFraction &c);
    CFraction operator/=(CFraction &c);
};
int gcd(int a,int b)
{
return a%b==0?b:gcd(b,a%b);
}
CFraction::CFraction(int n,int d)
{
    nume=n;
    deno=d;
}
void CFraction::setCFraction(int n,int d)
{
    nume=n;
    deno=d;
}
CFraction change(CFraction &c)
{
    int t,a,b;
    a=c.nume;
    b=c.deno;
    t=gcd(a,b);
    c.nume/=t;
    c.deno/=t;
    return c;
}
void CFraction::display()
{
    if(nume!=0&&deno!=0)
    cout<<nume<<"/"<<deno<<endl;
    else if(nume==0&&deno!=0)
        cout<<"0"<<endl;
    else
        cout<<"error"<<endl;

}
CFraction CFraction::operator+(CFraction &c)
{
    CFraction p;
    p.nume=nume*c.deno+deno*c.nume;
    p.deno=deno*c.deno;
    return change(p);
}
CFraction CFraction::operator-(CFraction &c)
{
    CFraction p;
    p.nume=nume*c.deno-deno*c.nume;
    p.deno=deno*c.deno;
    return change(p);
}
CFraction CFraction::operator*(CFraction &c)
{
    CFraction p;
    p.nume=nume*c.nume;
    p.deno=deno*c.deno;
    return change(p);
}
CFraction CFraction::operator/(CFraction &c)
{
    CFraction p;
    p.nume=nume*c.deno;
    p.deno=deno*c.nume;
    return change(p);
}
bool CFraction::operator > (CFraction &t)
{
    return (nume*t.deno>t.nume*deno);
}
bool CFraction::operator < (CFraction &t)
{
    return (nume*t.deno<t.nume*deno);
}
bool CFraction::operator >= (CFraction &t)
{
    return !(nume*t.deno<t.nume*deno);
}
bool CFraction::operator <= (CFraction &t)
{
    return !(nume*t.deno>t.nume*deno);
}
bool CFraction::operator == (CFraction &t)
{
    return !(nume*t.deno>t.nume*deno||nume*t.deno<t.nume*deno);
}
bool CFraction::operator != (CFraction &t)
{
    return (nume*t.deno>t.nume*deno||nume*t.deno<t.nume*deno);
}

//赋值运算符的重载
CFraction CFraction::operator+=(CFraction &c)
{
    nume=nume*c.deno+deno*c.nume;
    deno=deno*c.deno;
    return change(*this);
}
CFraction CFraction::operator-=(CFraction &c)
{
    nume=nume*c.deno-deno*c.nume;
    deno=deno*c.deno;
    return change(*this);
}
CFraction CFraction::operator*=(CFraction &c)
{
    nume=nume*c.nume;
    deno=deno*c.deno;
    return change(*this);
}
CFraction CFraction::operator/=(CFraction &c)
{
    nume=nume*c.deno;
    deno=deno*c.nume;
    return change(*this);
}
int main()
{
    CFraction t1(7,9),t2(11,9),t;
    cout<<"t1为：";
    t1.display();
    cout<<"t2为：";
    t2.display();
    cout<<"下面比较两个时间大小：\n";
    if (t1>t2) cout<<"t1>t2"<<endl;
    if (t1<t2) cout<<"t1<t2"<<endl;
    if (t1==t2) cout<<"t1＝t2"<<endl;
    if (t1!=t2) cout<<"t1≠t2"<<endl;
    if (t1>=t2) cout<<"t1≥t2"<<endl;
    if (t1<=t2) cout<<"t1≤t2"<<endl;

    t=t1+t2;
    t.display();
    t=t1-t2;
    t.display();
    t=t1*t2;
    t.display();
    t=t1/t2;
    t.display();
    t1+=t2;
    t1.display();
    t1-=t2;
    t1.display();
    t1*=t2;
    t1.display();
    t1/=t2;
    t1.display();
    return 0;
}

运行结果：

学习心得：正在追赶中，好好加油，但不要图块。