Catchable fatal error: Object of class DateTime could not be converted to string inF:\project\public\web.php on line 54
决解方案一、
$tmptsql="select * from mytable";
$tmpstmt=sqlsrv_query($conn,$tmptsql);
$tmprs=sqlsrv_fetch_array($tmpstmt);
if( $tmpstmt === false )
{
echo "Error in statement preparation/execution.\n";
die( print_r( sqlsrv_errors(), true));
}
/* Make the first row of the result set available for reading. */
if( sqlsrv_fetch( $tmpstmt ) === false )
{
echo "Error in retrieving row.\n";
die( print_r( sqlsrv_errors(), true));
}
echo sqlsrv_get_field( $tmpstmt, 2,SQLSRV_PHPTYPE_STRING(SQLSRV_ENC_CHAR));
决解方案二、
SELECT convert(char,你的日期字段,120) as date2 FROM table
mssql默认以系统时间格式输出,你可以调整系统的时间格式来解决
当然是在程序里解决比较灵活,convert(char,date,N)输出的各中样式
N 日期样式
0 04 2 2005 9:06AM
1 04/02/05
2 05.04.02
3 02/04/05
4 02.04.05
5 02-04-05
6 02 04 05
7 04 02, 05
8 09:06:18
9 04 2 2005 9:06:18:857AM
10 04-02-05
11 05/04/02
12 050402
13 02 04 2005 09:06:18:857
14 09:06:18:857
20 2005-04-02 09:06:18
21 2005-04-02 09:06:18.857
22 04/02/05 9:06:18 AM
23 2005-04-02
24 09:06:18
25 2005-04-02 09:06:18.857
100 04 2 2005 9:06AM
101 04/02/2005
102 2005.04.02
103 02/04/2005
104 02.04.2005
105 02-04-2005
106 02 04 2005
107 04 02, 2005
108 09:06:18
109 04 2 2005 9:06:18:857AM
110 04-02-2005
111 2005/04/02
112 20050402
113 02 04 2005 09:06:18:857
114 09:06:18:857
120 2005-04-02 09:06:18
121 2005-04-02 09:06:18.857
126 2005-04-02T09:06:18.857