POJ 2524 Ubiquitous Religions 【并查集】

解题思路:输入总人数 n,和m组数据;即和杭电畅通工程相类似,对这m组数据做合并操作后,求最后一共有多少块区域。

#include<stdio.h>
int pre[50001];
int find(int root)
{
	if(root!=pre[root])
		pre[root]=find(pre[root]);
	return pre[root];
}
void unionroot(int x,int y)
{
	int root1,root2;
	root1=find(x);
	root2=find(y);
	if(x!=y)
	{
		pre[root1]=root2;
	}

}

int main()
{
	int n;
	int i;
	int x,y;
	long int m;
	int tag=1;
	while(scanf("%d %d",&n,&m)!=EOF&&(n||m))
	{
		int sum=0;

		for(i=0;i<n;i++)
			pre[i]=i;
		while(m--)
		{
		scanf("%d %d",&x,&y);
		unionroot(x,y);
		}
		for(i=0;i<n;i++)
		{
			if(find(i)==i)
				sum++;
		}
		printf("Case %d: %d\n",tag,sum);
		tag++;

	}
}
时间: 2024-11-05 13:37:41

POJ 2524 Ubiquitous Religions 【并查集】的相关文章

POJ 2524 Ubiquitous Religions (幷查集)

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 23090   Accepted: 11378 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi

[ACM] POJ 3295 Ubiquitous Religions (并查集)

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 23093   Accepted: 11379 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi

poj 2524:Ubiquitous Religions(并查集,入门题)

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 23997   Accepted: 11807 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi

POJ 2524 Ubiquitous Religions Union Find 并查集

本题是标准的并查集了,最后利用这些集求有多少独立集. 所以这里也写个标准程序过了. 最后查找独立集合: 看有多少个节点的父母节点是自己的,那么就是独立集合了.自己做自己的父母当然最独立的了,没有任何依赖,呵呵. #include <stdio.h> const int MAX_N = 50001; //const int MAX_M = MAX_N/2 * (MAX_N-1) + 1; int N, M; struct SubSet { int p, r; }; SubSet sub[MAX_

poj 2524 Ubiquitous Religions(并查集)

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 23168   Accepted: 11404 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi

POJ 2524 Ubiquitous Religions(宗教种类:并差集)

链接:http://poj.org/problem?id=2524 Ubiquitous Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 27774 Accepted: 13610 Description There are so many different religions in the world today that it is difficult to keep track of them al

POJ 2524 Ubiquitous Religions (简单并查集,三种方式)

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 30791   Accepted: 14928 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi

POJ - 2524 Ubiquitous Religions(简单并查集)

Ubiquitous Religions Time Limit: 5000MS   Memory Limit: 65536KB   64bit IO Format: %I64d & %I64u Submit Status Description 当今世界有很多不同的宗教,很难通晓他们.你有兴趣找出在你的大学里有多少种不同的宗教信仰. 你知道在你的大学里有n个学生(0 < n <= 50000) .你无法询问每个学生的宗教信仰.此外,许多学生不想说出他们的信仰.避免这些问题的一个方法是问

POJ 2524 (简答并查集) Ubiquitous Religions

题意:有编号为1到n的学生,然后有m组调查,每组调查中有a和b,表示该两个学生有同样的宗教信仰,问最多有多少种不同的宗教信仰 简单并查集 1 //#define LOCAL 2 #include <iostream> 3 #include <cstdio> 4 #include <cstring> 5 using namespace std; 6 7 const int maxn = 50000 + 10; 8 int parent[maxn], n, m; 9 10

POJ 2524 Ubiquitous Religions

F - Ubiquitous Religions Time Limit:5000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2524 Description 当今世界有很多不同的宗教,很难通晓他们.你有兴趣找出在你的大学里有多少种不同的宗教信仰. 你知道在你的大学里有n个学生(0 < n <= 50000) .你无法询问每个学生的宗教信仰.此外,许多学生