前言
本篇文章将要学习RxSwift
中四种转换操作符:
map
flatMap
flatMapLatest
scan
map
通过使用一个闭包函数将原来的Observable
序列转换为一个新的Observable
序列。
let disposeBag = DisposeBag()
Observable.of(1,2,3).map({return 10 * $0}).subscribe({print($0)}).disposed(by: disposeBag)
打印结果:
next(10)
next(20)
next(30)
completed
flatMap
将一个Observable
序列转换为另一个Observable
序列,并且合并两个Observable
序列。会按时间顺序接收两个序列发出的元素。
let disposeBag = DisposeBag()
struct Player {
var score:Variable<Int>
}
let man = Player(score: Variable(80))
let women = Player(score: Variable(90))
let player = Variable(man)
player.asObservable().flatMap({$0.score.asObservable()}).subscribe(onNext: {print($0)}).disposed(by: disposeBag)
man.score.value = 85
player.value = women
man.score.value = 95
women.score.value = 100
打印结果:
80
85
90
95
100
flatMapLatest
flatMapLatest
同flatMap
一样,也是将一个序列转换为另一个序列,flatMapLatest
只会从最近的序列中发出事件。
flatMapLatest
=map
+switchLatest
- 疑问:感觉和
switchLatest
没什么区别啊。(有哪位大佬帮忙解答一下么)
let disposeBag = DisposeBag()
struct Player {
var score:Variable<Int>
}
let man = Player(score: Variable(80))
let women = Player(score: Variable(90))
let player = Variable(man)
player.asObservable().flatMapLatest({$0.score.asObservable()}).subscribe(onNext: {print($0)}).disposed(by: disposeBag)
man.score.value = 85
player.value = women
man.score.value = 95
women.score.value = 100
打印结果:
80
85
90
100
scan
scan
就是提供一个初始化值,然后使用计算闭包不断将前一个元素和后一个元素进行处理,并将处理结果作为单个元素的Observable
序列返回。
let disposeBag = DisposeBag()
Observable.of(10, 100, 1000)
.scan(2) { aggregateValue, newValue in
aggregateValue + newValue
}
.subscribe(onNext: { print($0) })
.disposed(by: disposeBag)
打印结果:
12
112
1112
致谢
如果发现有错误的地方,欢迎评论,感谢!
时间: 2024-10-11 20:18:04