ACM试题 - 最长公共子序列 - 动态规划方法

ACM试题题源-(最长公共子序列)：http://acm.nyist.net/JudgeOnline/problem.php?pid=36

提交代码：

    import java.util.Scanner;

    public class Main {
        public static void main(String[] args) {
            Scanner cin = new Scanner(System.in);
            int n = cin.nextInt();
            int[] len = new int[n];
            for (int k = 0; k < n; k++) {
                String s1 = cin.next();
                String s2 = cin.next();
                int[][] m = new int[s1.length()+1][s2.length()+1];

                for (int i = 0; i < s1.length(); i++) {
                    for (int j = 0; j < s2.length(); j++) {
                        m[i][j] = 0;
                    }
                }

                for (int i = 0; i < s1.length(); i++) {
                    for (int j = 0; j < s2.length(); j++) {
                        if (s1.charAt(i) == s2.charAt(j)) {
                            m[i + 1][j + 1] = m[i][j] + 1;
                        } else {
                            m[i + 1][j + 1] = Math.max(m[i][j + 1], m[i + 1][j]);
                        }
                    }
                }

                len[k] = m[s1.length()][s2.length()];
            }
            for (int i = 0; i < n; i++) {
                System.out.println(len[i]);
            }

        }
    }

参考资料：http://blog.chinaunix.net/uid-26548237-id-3374211.html

ACM试题 - 最长公共子序列 - 动态规划方法