用企业微信发送告警

1.遇到的坑

 {"errcode":40001,"errmsg":"invalid credential, hint: [1507881186_cb1093c9bcaedaf108b7ce2ea10f2d38]"}
40001 不合法的secret参数  secret在应用详情/通讯录管理助手可查看
排查secret的取值也没有错啊。就郁闷了。

最后发现问题：是corpid写错了。把企业id写成了应用id。
因为“全局错误码”里没有提到corpid错误了会造成40001错误，所以一直以为是scerent的错。

参考：https://www.cnblogs.com/luoahong/articles/9018223.html

2.实用Python脚本

[[email protected] ~]# cat test_jj.py
#!python3
# -*- coding: utf-8 -*-

import json
import requests

class WeChat(object):
    def __init__(self, corpid, secret, agentid):
        self.url = "https://qyapi.weixin.qq.com"
        self.corpid = corpid
        self.secret = secret
        self.agentid = agentid

    # 获取企业微信的 access_token
    def access_token(self):
        url_arg = ‘/cgi-bin/gettoken?corpid={id}&corpsecret={crt}‘.format(
            id=self.corpid, crt=self.secret)
        url = self.url + url_arg
        response = requests.get(url=url)
        print(‘i am here‘)
        text = response.text
        print(text)
        self.token = json.loads(text)[‘access_token‘]

    # 构建消息格式
    def messages(self, msg):
        values = {
            "touser": ‘@all‘,
            "msgtype": ‘text‘,
            "agentid": self.agentid,
            "text": {‘content‘: msg},
            "safe": 0
        }
        # python 3
        # self.msg = (bytes(json.dumps(values), ‘utf-8‘))
        # python 2
        self.msg = json.dumps(values)

    # 发送信息
    def send_message(self, msg):
        self.access_token()
        self.messages(msg)

        send_url = ‘{url}/cgi-bin/message/send?access_token={token}‘.format(
            url=self.url, token=self.token)
        response = requests.post(url=send_url, data=self.msg)
        errcode = json.loads(response.text)[‘errcode‘]

        if errcode == 0:
            print(‘Succesfully‘)
        else:
            print(‘Failed‘)
#使用示例：
corpid = "wwdbe2bhaha48965a3012"
secret = "-rLV8ahtMIcYlRZMhahaik7y5ikASozwjjppx8ZPaBXyk"
agentid = ‘10200237‘
msg = "supply high quolity and low price product......"

wechat = WeChat(corpid, secret, agentid)
wechat.access_token()
wechat.send_message(msg)

原文地址：https://www.cnblogs.com/hixiaowei/p/10804516.html