227. Basic Calculator

1. 问题描述

Implement a basic calculator to evaluate a simple expression string.

The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero.

You may assume that the given expression is always valid.

Some examples:

"3+2*2" = 7
" 3/2 " = 1
" 3+5 / 2 " = 5

Note: Do not use the eval built-in library function.

Tags:String

Similar Problems:(H)Basic Calculator、(H)Expression Add Operators

Solution:

class Solution {
public:
    int calculate(string s) {

    }
};  

2. 解答思路

2.1 合法性判断

  • 空字符串
  • 在第一个数字字符(‘0‘~‘9‘)出现前(假设在位置i),则位置0到位置i的字符只能为空格‘ ’或一个正负号‘+’或‘-’号
  • 除数字、加、减、乘、除、空格字符外,其他字符均为非法字符,返回0。同时,需设置全局标志位,与计算结果为0进行区分
  • 有没有可能多个运算符字符相邻?e.g. "- +  /"、“*/-” etc. 不会,因为题目中说You may assume that the given expression is always valid.
  • 若有溢出如何处理

2.2 整数提取

  • 如何从相邻的多个空格与数字字符的串中,提取出整数

2.3 算法

3. 代码

4. 反思

时间: 2024-10-29 19:10:31

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