九的余数(弃九法)

  Hexo博客崩了,以后不想动了,QAQ。(博客:empirefree.top

A*B Problem

时间限制:1000 ms  |  内存限制:65535 KB

难度:2

描述

设计一个程序求出A*B,然后将其结果每一位相加得到C,如果C的位数大于等于2,继续将C的各位数相加,直到结果是个一位数k。

例如:

6*8=48;

4+8=12;

1+2=3;

输出3即可。

输入
第一行输入一个数N(0<N<=1000000),表示N组测试数据。
随后的N行每行给出两个非负整数m,n(0<=m,n<=10^12)。
输出
对于每一行数据,输出k。
样例输入
3
6 8
1234567 67
454 1232
样例输出
3
4
5
来源
szhhck的水库
上传者
ACM_宋志恒
弃九法:若一个数字的各个位数相加能被九整除,则这个数能被九整除。
实际应用:
  123456789 % 9  = sum(每个位数 % 9)
所以:这题也是类似,每个位数相加不断%9(虽然题目没说,但是意思差不多) = 直接% 9 ,然后a * b即可.(注意a, b 一开始为0的情况)

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 69                                                                     :r7Ji;r7;::;;.
 70                                                                         .                                                                             **/
 71
 72 #include <iostream>
 73 #include <algorithm>
 74 #include <vector>
 75 #include <stdlib.h>
 76 #include <string.h>
 77 #include <math.h>
 78 #include <queue>
 79 #include <stdio.h>
 80 using namespace std;
 81
 82 #define FFI(a, b) for(int i = a; i < b; i++)
 83 #define FFJ(a, b) for(int j = a; j < b; j++)
 84 #define FFK(a, b) for(int k = a; k < b; k++)
 85 #define RR(a, b) for(int i = a; i > b; i++)
 86 #define ME(a, b) memset(a, b, sizeof(a))
 87 #define SC(x) scanf("%d", &x)
 88 #define SCC(a, b) scanf("%d%d", &a, &b)
 89 #define PR(x) printf("%d\n", x)
 90 #define PRR(a, b) printf("%d%d\n", a, b);
 91 #define INF 0x3f3f3f3f
 92 #define MAX 202
 93 #define MOD 1000000007
 94 #define E 2.71828182845
 95 #define M 8
 96 #define N 6
 97 typedef long long LL;
 98 const double PI = acos(-1.0);
 99 typedef pair<int, int> Author;
100 vector<pair<string, int> > VP;
101
102 /*******************************************************************************************************************************************************/
103
104 int main(void){
105 //    #ifdef Empirefree
106 //        freopen("in.txt", "r", stdin);
107 //        freopen("out.txt", "w", stdout);
108 //    #endif
109 //
110 //    ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
111     int n;LL a, b, s;
112
113     SC(n);
114     //弃九法
115     while(n--){
116
117         scanf("%lld%lld", &a, &b);
118         if(!a || !b){
119             printf("0\n");
120             continue;
121         }
122         s = (a % 9) * (b % 9) % 9;
123
124         printf("%lld\n", s == 0 ? 9 : s);
125     }
126
127     return EXIT_SUCCESS;
128 }        

Empirefree.top

再来2道实际例题

http://acm.nyist.edu.cn/JudgeOnline/problem.php?pid=205

http://acm.nyist.edu.cn/JudgeOnline/problem.php?pid=105

原文地址:https://www.cnblogs.com/meditation5201314/p/9409270.html

时间: 2024-11-05 18:49:03

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