Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <). It is guaranteed that the number of digits of Z is an even number.
Output Specification:
For each case, print a single line Yes
if it is such a number, or No
if not.
Sample Input:
3
167334
2333
12345678
Sample Output:
Yes
No
No
这道题题意是前一半乘后一半,看看最终数能不能被原数字整除。
我们仅需要进行用substr进行分解就可以。
如果出现浮点错误,就是表示除以了0,我们要考虑后半部分不为0的情况
#include <iostream> #include <string> using namespace std; int main(){ int N; string tmp; cin >> N; while(N--) { cin >> tmp; int num = stoi(tmp); int a = stoi(tmp.substr(0, tmp.size()/2)); int b = stoi(tmp.substr(tmp.size()/2)); if(a * b != 0 && num % (a * b) == 0) cout << "Yes" << endl; else cout << "No" << endl; } return 0; }
原文地址:https://www.cnblogs.com/littlepage/p/12236338.html