Oracle 方法

1、递归

 select zxdept
   from (select d.id, d.zxdept, d.RANK, d.fatherId
           from web_dept d
          start with d.id = 18022 --获取18022部门层级
                 and d.SHOWFLAG = 1
         connect by PRIOR fatherId = id) temp
  where temp.rank <= 4
  order by rank asc

结果：

1 分析及投后管理
2 财务部
3 财务部
4 管理中心

2、列拼接成行 wm_concat（）

 select replace(wm_concat(zxdept), ‘,‘, ‘/‘) as 部门名称
   from (select zxdept
           from (select d.id, d.zxdept, d.RANK, d.fatherId
                   from web_dept d
                  start with d.id = 18022--获取18022部门层级
                         and d.SHOWFLAG = 1--可用
                 connect by PRIOR fatherId = id) temp
          where temp.rank <= 4--四级以内
            and temp.rank >= 1--大于等于一级
          order by rank asc)

结果：管理中心/财务部/财务部/分析及投后管理

3、获取最新分组内所有一条记录

select *
  from ( --以 orderno 分组,查找分组内最新一条工作流日志
        select t.*,
                row_number() over(partition by orderno order by FORTIME desc) rn
          from (select *
                   from WORKFLOW_INSTANCE_LOG
                  where orderno in (select to_char(ID) as id
                                      from HR_DIMISSION
                                     where USERCODE = ‘B143130‘
                                       and (FLAGSAVE = 2 or FLAGSAVE = 9) -- 离职单
                                    union all
                                    select to_char(ID) as id
                                      from HR_ConFirm
                                     where USERCODE = ‘B143130‘
                                       and FLAGSAVE = 2 -- 转正单
                                    union all
                                    select to_char(ID) as id
                                      from HR_Transposal
                                     where USERCODE = ‘B143130‘
                                       and FLAGSAVE = 2 -- 调岗单
                                    )) t)
 where rn = 1