CodeForces 722A Broken Clock (水题)

题意：给定一个时间，然后改最少的数字，使得它成为12进制或者24进制。

析：24进制主要判是不是大于23，如果是把第一位变成0，12进制判是不是大于12，如果是再看第二位是不是0，是0，第一位变成1，不是第一位变成0，

如果等于0，第一位变成1，至于分钟，只要判是不是大于59，是把第一位变成0.

代码如下：

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
#include <cctype>
#include <cmath>
#include <stack>
//#include <tr1/unordered_map>
#define freopenr freopen("in.txt", "r", stdin)
#define freopenw freopen("out.txt", "w", stdout)
using namespace std;
//using namespace std :: tr1;

typedef long long LL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const double inf = 0x3f3f3f3f3f3f;
const LL LNF = 0x3f3f3f3f3f3f;
const double PI = acos(-1.0);
const double eps = 1e-8;
const int maxn = 1e5 + 5;
const LL mod = 1e9 + 7;
const int N = 1e6 + 5;
const int dr[] = {-1, 0, 1, 0, 1, 1, -1, -1};
const int dc[] = {0, 1, 0, -1, 1, -1, 1, -1};
const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
inline LL gcd(LL a, LL b){  return b == 0 ? a : gcd(b, a%b); }
inline int gcd(int a, int b){  return b == 0 ? a : gcd(b, a%b); }
int n, m;
const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
inline int Min(int a, int b){ return a < b ? a : b; }
inline int Max(int a, int b){ return a > b ? a : b; }
inline LL Min(LL a, LL b){ return a < b ? a : b; }
inline LL Max(LL a, LL b){ return a > b ? a : b; }
inline bool is_in(int r, int c){
    return r >= 0 && r < n && c >= 0 && c < m;
}

int main(){
    while(scanf("%d", &n) == 1){
        string s;
        cin >> s;
        int h = (s[0] - ‘0‘) * 10 + s[1] - ‘0‘;
        int m = s[3] - ‘0‘;
        if(m > 5)  s[3] = ‘0‘;
        if(n == 24){
            if(h > 23)  s[0] = ‘0‘;
        }
        else{
            if(h > 12){
                if(s[1] != ‘0‘)  s[0] = ‘0‘;
                else s[0] = ‘1‘;
            }
            if(!h) s[0] = ‘1‘;
        }
        cout << s << endl;
    }
    return 0;
}