(LeetCode)Valid Anagram --- 有效的混排字符串

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,

s = "anagram", t = "nagaram", return true.

s = "rat", t = "car", return false.

Note:

You may assume the string contains only lowercase alphabets.

Follow up:

What if the inputs contain unicode characters? How would you adapt your solution to such case?

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解题分析：

此题的意思很容易理解，意思就是给出两个字符串，然后判断是不是有一个混排成另一个字符串的。

确定是混排的话返回 True, 不正确的话返回 False.

思路是先将字符串转化为 list 然后进行排序，最后在进行比较，如果是有效的话，绝对是相等的。

# -*- coding:utf-8 -*-
__author__ = 'jiuzhang'
class Solution(object):
    def isAnagram(self, s, t):
        s_list = []
        t_list = []
        if len(s) != len(t):
            return False
        else:
            for i in range(len(s)):
                s_list.append(s[i])
                t_list.append(t[i])
            s_list.sort()
            t_list.sort()
            flag = 0
            for i in range(len(s_list)):
                if s_list[i] == t_list[i]:
                    flag += 1
                else:
                    flag += 0
            if flag == len(s_list):
                return True
            else:
                return False