xml文件格式如下
1 <?xml version="1.0" encoding="utf-8" ?> 2 <root> 3 <appKey>abcdefg</appKey> 4 <appSecret>hijklmn</appSecret> 5 <serverUrl>opqrst</serverUrl> 6 <accessToken>uvwxyz</accessToken> 7 </root>
读取格式如下,我是放在构造函数里面
先声明几个私有变量接受
private string SERVER_URL; private string accessToken; private string appKey; private string appSecret;
3 //判断可执行文件下有么有JD_API.xml文件,也就是debug目录下 4 if (File.Exists(Application.StartupPath + "\\JD_API.xml")) 5 { 6 XmlDocument xml = new XmlDocument(); 7 xml.Load(Application.StartupPath+"\\JD_API.xml");//加载xml文件 8 appKey = xml.SelectSingleNode("root/appKey").InnerText;//读取xml节点 9 appSecret = xml.SelectSingleNode("root/appSecret").InnerText; 10 SERVER_URL = xml.SelectSingleNode("root/serverUrl").InnerText; 11 accessToken = xml.SelectSingleNode("root/accessToken").InnerText; 12 }
时间: 2024-11-08 17:56:27