题目链接:https://vjudge.net/problem/UVA-12504
题目翻译摘自《算法禁赛入门经典》
题目大意
在本题中,字典是若干键值对,其中键为小写字母组成的字符串,值为没有前导零或正号的非负整数(-4,03 和 +77 都是非法的,注意该整数可以很大)。输入一个旧字典和一个新字典,计算二者的变化。输入的两个字典中键都是唯一的,但是排列顺序任意。
输入包含两行,各包含不超过100个字符,即旧字典和新字典。输出格式如下:
- 如果至少有一个新增键,打印一个“+”号,然后是所有新增键,按字典序从小到大排列。
- 如果至少有一个删除键,打印一个“-”号,然后是所有删除键,按字典序从小到大排列。
- 如果至少有一个修改键,打印一个“*”号,然后是所有修改键,按字典序从小到大排列。
- 如果没有任何修改,输出No changes。
分析
搞两个有序表一一对比即可。
代码如下
1 #include <bits/stdc++.h> 2 using namespace std; 3 4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); 5 #define Rep(i,n) for (int i = 0; i < (n); ++i) 6 #define For(i,s,t) for (int i = (s); i <= (t); ++i) 7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i) 8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i) 9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i) 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i) 12 13 #define pr(x) cout << #x << " = " << x << " " 14 #define prln(x) cout << #x << " = " << x << endl 15 16 #define LOWBIT(x) ((x)&(-x)) 17 18 #define ALL(x) x.begin(),x.end() 19 #define INS(x) inserter(x,x.begin()) 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end()) 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower); 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper); 24 25 #define ms0(a) memset(a,0,sizeof(a)) 26 #define msI(a) memset(a,inf,sizeof(a)) 27 #define msM(a) memset(a,-1,sizeof(a)) 28 29 #define MP make_pair 30 #define PB push_back 31 #define ft first 32 #define sd second 33 34 template<typename T1, typename T2> 35 istream &operator>>(istream &in, pair<T1, T2> &p) { 36 in >> p.first >> p.second; 37 return in; 38 } 39 40 template<typename T> 41 istream &operator>>(istream &in, vector<T> &v) { 42 for (auto &x: v) 43 in >> x; 44 return in; 45 } 46 47 template<typename T1, typename T2> 48 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) { 49 out << "[" << p.first << ", " << p.second << "]" << "\n"; 50 return out; 51 } 52 53 inline int gc(){ 54 static const int BUF = 1e7; 55 static char buf[BUF], *bg = buf + BUF, *ed = bg; 56 57 if(bg == ed) fread(bg = buf, 1, BUF, stdin); 58 return *bg++; 59 } 60 61 inline int ri(){ 62 int x = 0, f = 1, c = gc(); 63 for(; c<48||c>57; f = c==‘-‘?-1:f, c=gc()); 64 for(; c>47&&c<58; x = x*10 + c - 48, c=gc()); 65 return x*f; 66 } 67 68 template<class T> 69 inline string toString(T x) { 70 ostringstream sout; 71 sout << x; 72 return sout.str(); 73 } 74 75 inline int toInt(string s) { 76 int v; 77 istringstream sin(s); 78 sin >> v; 79 return v; 80 } 81 82 //min <= aim <= max 83 template<typename T> 84 inline bool BETWEEN(const T aim, const T min, const T max) { 85 return min <= aim && aim <= max; 86 } 87 88 typedef long long LL; 89 typedef unsigned long long uLL; 90 typedef pair< double, double > PDD; 91 typedef pair< int, int > PII; 92 typedef pair< int, PII > PIPII; 93 typedef pair< string, int > PSI; 94 typedef pair< int, PSI > PIPSI; 95 typedef set< int > SI; 96 typedef set< PII > SPII; 97 typedef vector< int > VI; 98 typedef vector< double > VD; 99 typedef vector< VI > VVI; 100 typedef vector< SI > VSI; 101 typedef vector< PII > VPII; 102 typedef map< int, int > MII; 103 typedef map< int, string > MIS; 104 typedef map< int, PII > MIPII; 105 typedef map< PII, int > MPIII; 106 typedef map< string, int > MSI; 107 typedef map< string, string > MSS; 108 typedef map< PII, string > MPIIS; 109 typedef map< PII, PII > MPIIPII; 110 typedef multimap< int, int > MMII; 111 typedef multimap< string, int > MMSI; 112 //typedef unordered_map< int, int > uMII; 113 typedef pair< LL, LL > PLL; 114 typedef vector< LL > VL; 115 typedef vector< VL > VVL; 116 typedef priority_queue< int > PQIMax; 117 typedef priority_queue< int, VI, greater< int > > PQIMin; 118 const double EPS = 1e-8; 119 const LL inf = 0x7fffffff; 120 const LL infLL = 0x7fffffffffffffffLL; 121 const LL mod = 1e9 + 7; 122 const int maxN = 1e4 + 7; 123 const LL ONE = 1; 124 const LL evenBits = 0xaaaaaaaaaaaaaaaa; 125 const LL oddBits = 0x5555555555555555; 126 127 int T; 128 string tmp; 129 MSS A, B; 130 MIS mis = {MP(0, "+"), MP(1, "-"), MP(2, "*")}; 131 132 void analysis(MSS &x, string s) { 133 foreach(i, s) if(*i == ‘{‘ || *i == ‘}‘ || *i == ‘,‘ || *i == ‘:‘) *i = ‘ ‘; 134 stringstream sin(s); 135 string a, b; 136 137 while(sin >> a >> b) x[a] = b; 138 } 139 140 int main(){ 141 //freopen("MyOutput.txt","w",stdout); 142 //freopen("input.txt","r",stdin); 143 //INIT(); 144 cin >> T; 145 while(T--) { 146 set< string > changes[3]; 147 A.clear(); 148 B.clear(); 149 cin >> tmp; 150 analysis(A, tmp); 151 cin >> tmp; 152 analysis(B, tmp); 153 154 auto itA = A.begin(), itB = B.begin(); 155 while(itA != A.end() && itB != B.end()) { 156 if(itA->ft == itB->ft) { 157 if(itA->sd != itB->sd) changes[2].insert(itA->ft); 158 ++itA; 159 ++itB; 160 } 161 else if(itA->ft > itB->ft) { 162 changes[0].insert(itB->ft); 163 ++itB; 164 } 165 else { 166 changes[1].insert(itA->ft); 167 ++itA; 168 } 169 } 170 171 while(itA != A.end()) { 172 changes[1].insert(itA->ft); 173 ++itA; 174 } 175 176 while(itB != B.end()) { 177 changes[0].insert(itB->ft); 178 ++itB; 179 } 180 181 if(changes[0].empty() && changes[1].empty() && changes[2].empty()) printf("No changes\n\n"); 182 else { 183 Rep(i, 3) { 184 if(!changes[i].empty()) { 185 cout << mis[i]; 186 foreach(j, changes[i]) { 187 if(j != changes[i].begin()) cout << ","; 188 cout << *j; 189 } 190 cout << endl; 191 } 192 } 193 cout << endl; 194 } 195 } 196 return 0; 197 }
原文地址:https://www.cnblogs.com/zaq19970105/p/11074863.html
时间: 2024-11-06 07:22:58