数据结构（C语言）第1章

main.c

 1 #include "ch_1.h"
 2
 3 int main()
 4 {
 5     Triplet p;
 6     Status i;
 7     ElemType m;
 8     i = InitList(&p,1,2,3);
 9     printf("InitList: %d,%d,%d\n", p[0],p[1],p[2]);
10
11     i = Get(p, 2, &m);
12     if (i == OK)
13         printf("%d\n", m);
14
15     Put(p, 2, 3);
16     if (i == OK)
17         printf("%d,%d,%d\n", p[0], p[1], p[2]);
18
19     i = IsAscending(p);
20     printf("yes:1 no: 0  %d\n", i);
21
22     i = IsDesending(p);
23     printf("yes:1 no: 0     %d\n", i);
24
25     printf("max: %d\n", Max(p, &m));
26
27     DestroyTriplet(&p);
28     return 0;
29 }

ch_1.h

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #define OK 1
 4 #define ERROR 0
 5 #define OVERFLOW -2
 6 typedef int ElemType;
 7 typedef int Status;
 8 typedef ElemType *Triplet;
 9
10 Status InitList(Triplet *T, ElemType v1, ElemType v2, ElemType v3) //构造三元数组
11 {
12     *T = (ElemType*)malloc(3 * sizeof(ElemType));
13     if (!*T)
14         exit(OVERFLOW);
15     (*T)[0] = v1;
16     (*T)[1] = v2;
17     (*T)[2] = v3;
18     return OK;
19 }
20
21 Status Get(Triplet T, int i, ElemType *e)        //用e返回相应的元素值
22 {
23     if (i < 1 || i > 3)
24         return ERROR;
25     *e = T[i - 1];
26     return OK;
27 }
28
29 Status Put(Triplet T, int i, ElemType e)        //改变相应的元素值
30 {
31     if (i < 1 || i > 3)
32         return ERROR;
33     T[i - 1] = e;
34 }
35
36 Status IsAscending(Triplet T) //升序
37 {
38     return((T[0] <= T[1]) && (T[1] <= T[2]));
39 }
40
41 Status IsDesending(Triplet T) //降序
42 {
43     return((T[0] >= T[1]) && (T[1] >= T[2]));
44 }
45
46 Status Max(Triplet T, ElemType *e)
47 {
48     if (T[0] >= T[1])
49     {
50         if (T[0] >= T[2])
51             *e = T[0];
52         else
53             *e = T[2];
54     }
55
56     else
57     {
58         if (T[1] >= T[2])
59             *e = T[1];
60         else
61             *e = T[2];
62     }
63 }
64
65 Status DestroyTriplet(Triplet *T)
66 {
67     free(*T);
68     *T = NULL;
69     return OK;
70 }

运行结果：

InitList: 1,2,3
2
1,3,3
yes:1 no: 0 1
yes:1 no: 0 0
max: 3