Mysql group by top N的问题

在日常工作中,经常要查询分组的前几名.oracle中可以通过row_num来支持查询,mysql暂时不支持row_num.那么如何来完成这个需求呢?

例如：

表中的数据：

+--------+-------+-----+

| Person | Group | Age |

+--------+-------+-----+

| Bob    | 1     | 32  |

| Jill   | 1     | 34  |

| Shawn  | 1     | 42  |

| Jake   | 2     | 29  |

| Paul   | 2     | 36  |

| Laura  | 2     | 39  |

+--------+-------+-----+

期望的结果：

+--------+-------+-----+

| Shawn  | 1     | 42  |

| Jill   | 1     | 34  |

| Laura  | 2     | 39  |

| Paul   | 2     | 36  |

+--------+-------+-----+

方式一:借鉴oracle中row_num的思想,在sql中增加伪列.

set@num :=0,@group:=‘‘;select person,`group`, age

from(select person,`group`, age,@num :=if(@group=`group`,@num +1,1)as row_number,@group:=`group`asdummyfrom mytable

  orderby`Group`, Age desc, person

)as x

where x.row_number <=2;

方式二:利用关联子查询

SELECT a.person, a.group, a.age FROM person AS a WHERE(SELECT COUNT(*)FROM person AS b

WHERE b.group= a.groupAND b.age >= a.age)<=2ORDERBY a.groupASC, a.age DESC

ps：

1.在我处理的实际问题而言,方式一的效率明显高于方式二.

参考链接:http://stackoverflow.com/questions/12113699/get-top-n-records-for-each-group-of-grouped-results.

Mysql group by top N的问题,码迷,mamicode.com