随机性问题
水塘抽样算法可保证每个样本被抽到的概率相等
使用场景:从包含n个项目的集合S中选取k个样本,其中n为一很大或未知的数量,尤其适用于不能把所有n个项目都存放到主内存的情况
Knuth洗牌算法
拿起第i
张牌时,只从它前面的牌随机选出j,或从它后面的牌随机选出j交换即可
1 class Solution { 2 public: 3 Solution(vector<int>& nums) { 4 v = nums; 5 } 6 7 /** Resets the array to its original configuration and return it. */ 8 vector<int> reset() { 9 return v; 10 } 11 12 /** Returns a random shuffling of the array. */ 13 vector<int> shuffle() { 14 vector<int> res = v; 15 for (int i = 0; i < res.size(); ++i) { 16 int t = i + rand() % (res.size() - i); 17 swap(res[i], res[t]); 18 } 19 return res; 20 } 21 vector<int> v; 22 }; 23 24 /** 25 * Your Solution object will be instantiated and called as such: 26 * Solution* obj = new Solution(nums); 27 * vector<int> param_1 = obj->reset(); 28 * vector<int> param_2 = obj->shuffle(); 29 */
原文地址:https://www.cnblogs.com/demian/p/11240184.html
时间: 2024-10-17 08:47:01