题目
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
分析
删除链表中重复元素结点。
该题目本质很简单,只需一次遍历。需要注意的是,要释放删除的结点空间。
AC代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if (head == NULL || head->next == NULL)
return head;
ListNode *p = head, *q = p->next;
while (p && q)
{
if (p->val == q->val)
{
ListNode *t = q;
p->next = q->next;
q = q->next;
//释放要删除的结点空间
delete t;
}
else{
p = p->next;
q = q->next;
}//elif
}//while
return head;
}
};
时间: 2024-10-09 10:05:17