2.1语法
public 返回值类型 方法名（）{
//方法体
}
2.2方法的调用语法
对象名.方法名
计算平均分和总成绩
1 public class Score {
2 /**
3 * 创建类 ScoreCalc 编写方法实现各功能 编写测试类
4 * 从键盘接收三门课分数，（java c# db）
5 * 计算三门课的平均分和总成绩，
6 * 编写成绩计算类实现功能 _______
7 */
8 int java;
9 int c;
10 int db;
11
12 public double avg() {
13 double a = (double) (java + c + db) / 3;
14 return a;
15 }
16
17 public int addAll() {
18
19 int ad = java + c + db;
20 return ad;
21 }
22
23 }
Score
1 import java.util.Scanner;
2
3
4 public class TestScore {
5 public static void main(String[] args) {
6 Score sc=new Score();
7 Scanner input=new Scanner(System.in);
8 System.out.println("请输入java成绩：");
9 sc.java=input.nextInt();
10 System.out.println("请输入c成绩：");
11 sc.c=input.nextInt();
12 System.out.println("请输入db成绩：");
13 sc.db=input.nextInt();
14
15 System.out.println(sc.addAll());//总成绩
16 System.out.println(sc.avg());//平均成绩
17 }
18
19 }
TestScore
package week2;
public class Manager {
String name;
String password;
/**
* 打印学员信息
*/
public void show() {
System.out.println("管理员名为："+name+"\n密码为："+password);
}
}
1 package week2;
2
3 public class TestManager {
4 public static void main(String[] args) {
5 Manager manager=new Manager();
6 manager.name="王铎";
7 manager.password="123";
8 manager.show();
9 }
10
11 }
TestManager
2.3用数组作为参数
package week2;
public class JavaScore {
public double avg(int[] scores) {
int sum = 0;
double avg1 = 0.0;
for (int i = 0; i < scores.length; i++) {
sum = sum + scores[i];
}
avg1 = (double) sum / scores.length;
return avg1;
}
public int max(int[] scores) {
int max1 = scores[0];
for (int i = 0; i < scores.length; i++) {
if (max1 < scores[i]) {// 最大值
max1 = scores[i];
}
}
return max1;
}
}
package week2;
import java.util.Scanner;
public class TestScore {
public static void main(String[] args) {
JavaScore javascore=new JavaScore();
int []scores=new int [4];
Scanner input=new Scanner(System.in);
System.out.println("请输入5名参赛者的平均成绩：");
for (int i = 0; i < scores.length; i++) {
scores[i]=input.nextInt();
}
//pingj
javascore.avg(scores);
}
}
2.4多个参数的方法
package week2;
public class StudentBz {
String[] names = new String[30];
// 添加学生信息
public void addName(String name) {
for (int i = 0; i < names.length; i++) {
if (names[i] == null) {
names[i] = name;
break;
}
}
}
// 展示学生信息
public void nameShow() {
for (int i = 0; i < names.length; i++) {
if (names[i] != null) {
System.out.print(names[i] + ",");
}
}
}
public boolean searchFind(int start, int end, String name) {
boolean find = false;// 标识查找的位置
for (int i = start - 1; i < end; i++) {// i=start-1sss数组下标
if (names[i].equals(name)) {
find = true;
break;
}
}
return find;
}
public boolean updateName(String newName, String oldName) {
boolean find = false;
// 查找老name
for (int i = 0; i < names.length; i++) {
if (oldName.equals(names[i])) {
names[i] = newName;
find = true;
break;
}
}
return find;
}
}
package week2;
import java.util.Scanner;
public class TestAdd {
public static void main(String[] args) {
StudentBz stu=new StudentBz();
for (int i = 0; i < 3; i++) {
Scanner input=new Scanner(System.in);
System.out.print("请输入学生姓名：");
String na=input.next();
stu.addName(na);
}
stu.nameShow();
boolean result=stu.searchFind(2, 5, "name2");
System.out.println(result);
boolean updateResult=stu.updateName("newName", "name2");
System.out.println("是否修改成功"+updateResult);
stu.nameShow();
}
}
2.5对象作为参数
1 package week2;
2
3 public class Student {
4 String name;
5 int age;
6 int no;
7 int score;
8
9 }
Student
1 package week2;
2
3 public class StudentBz2 {
4
5 Student students[] = new Student[30];
6
7 public void addStudent(Student student) {
8 for (int i = 0; i < students.length; i++) {
9 if (students[i] == null) {
10 students[i] = student;
11 break;
12 }
13
14 }
15
16 }
17
18 public void showStudent() {
19 for (int i = 0; i < students.length; i++) {
20 if (students[i] != null) {
21 System.out.println(students[i].name + "," + students[i].age
22 + "," + students[i].no + "," + students[i].score + ",");
23
24 }
25
26 }
27
28 }
29
30 }
StudentBz2
1 package week2;
2
3 import java.util.Scanner;
4
5 public class TestStudentBz2 {
6 public static void main(String[] args) {
7 StudentBz2 stubz=new StudentBz2();
8 Scanner input=new Scanner(System.in);
9 for (int i = 0; i < 2; i++) {
10 Student stu=new Student();//循环几次出现几个对象
11 System.out.print("请输入姓名：");
12 stu.name=input.next();
13 System.out.print("请输入年龄：");
14 stu.age=input.nextInt();
15 System.out.print("请输入学号：");
16 stu.no=input.nextInt();
17 System.out.print("请输入成绩：");
18 stu.score=input.nextInt();
19 stubz.addStudent(stu);
20 }
21 System.out.println();
22
23 stubz.showStudent();
24
25 }
26
27 }
TestStudentBz2
练习实现对客户姓名的排序
1 package week2;
2
3 import java.util.Arrays;
4
5 public class KH {
6
7 public void sortName(String []names) {
8 Arrays.sort(names);
9
10 }
11 }
KH
1 package week2;
2
3 public class KHTest {
4 public static void main(String[] args) {
5 String []names={"j","sds","sdssf","ssf"};
6 KH kh=new KH();
7 System.out.println("排序前");
8 for (int i = 0; i < names.length; i++) {
9 if (names[i]!=null) {
10 System.out.println(names[i]+",");
11
12 }
13
14 }
15 kh.sortName(names);
16 System.out.println("排序后");
17 for (int i = 0; i < names.length; i++) {
18 if (names[i]!=null) {
19 System.out.println(names[i]+",");
20
21
22 }
23
24
25 }
26 }
27
28 }
KHTest
带参数练习
1 package week2;
2
3 public class CustomerBiz {
4 String []customer=new String[30];
5
6 public void addName(String name) {
7 for (int i = 0; i < customer.length; i++) {
8 if (customer[i]==null) {
9 customer[i]=name;
10 break;
11
12 }
13
14
15 }
16
17
18 }
19
20
21 public void showNames() {
22 System.out.println("*****************");
23 System.out.println("客户姓名列表");
24
25 for (int i = 0; i < customer.length; i++) {
26 if (customer[i]!=null) {
27 System.out.println(customer[i]+",");
28
29 }
30
31
32 }
33
34
35
36 }
37
38 }
CustomerBiz
1 package week2;
2
3 import java.util.Scanner;
4
5 public class TestCustomer {
6 public static void main(String[] args) {
7 boolean con = false;
8 CustomerBiz cust = new CustomerBiz();
9 Scanner input = new Scanner(System.in);
10
11 for (int i = 0; i < 3; i++) {
12 System.out.print("请输入客户姓名：");
13 String na = input.next();
14 cust.addName(na);
15 System.out.println("是否继续（y/n）");
16 String n = input.next();
17
18 if (!n.equals("y")) {
19
20 }
21
22 }
23 cust.showNames();
24
25 }
26
27 }
TestCustomer
原文地址：https://www.cnblogs.com/IUnicorn/p/8419623.html
时间： 2024-07-31 13:22:23