会爆栈，dfs传参，只能传1个~~RMQLCA在线

#include<cstdio>
#include<cstring>
#include<algorithm>
#pragma comment(linker, "/STACK:1024000000, 1024000000")
#include<queue>
using namespace std;

const int M = 400015;
struct Edge{
    int v, next;
} edge[M << 1];
int cnt;
int F[M<<1], rmq[M << 1], P[M];
int dp[20][M<<1];
int E; int head[M];
void add_edge(int s, int v){
    edge[E].next = head[s];
    edge[E].v = v;
    head[s] = E ++;
}

int vis[M];
int dep[M];
void dfs(int u){
    cnt ++;
    F[cnt] = u;
    rmq[cnt] = dep[u];
    P[u] = cnt;
    vis[u] = 1;
    for(int i = head[u]; i != -1; i = edge[i].next){
        int v = edge[i].v;
        if(vis[v]) continue;
        dfs(v);
        cnt ++;
        rmq[cnt] = dep[u];
        F[cnt] = u;
    }
}

void RMQ(int n){
    for(int i = 1; i <= n; i ++) dp[0][i] = i;
    for(int j = 1; (1<<j) <= n; j ++) {
        int tmp = 1<<(j-1);
        for(int i = 1; i + tmp <= n; i ++){
            dp[j][i] = (rmq[dp[j-1][i]] < rmq[dp[j-1][i + tmp]])?dp[j-1][i]:dp[j-1][i + tmp];
        }
    }
}

int query(int L, int R){
    if(L > R) swap(L, R);
    int t = R - L+1;
    int k = 0;
    while(t >= (1<<(k+1))) k ++;
    return rmq[dp[k][L]] < rmq[dp[k][R-(1<<k) + 1]]?dp[k][L]:dp[k][R-(1<<k) + 1];
}
int solve(int a, int b){
    return F[query(P[a], P[b])];
}
int dis[M], vv[M];
void bfs(){
    queue<int> q;
    q.push(1);
    vv[1] = 1;
    dep[1] = 1;
    while(!q.empty()){
        int u = q.front(); q.pop();
        for(int i = head[u]; i != -1; i = edge[i].next){
            int v = edge[i].v;
            if(vv[v]) continue;
            dep[v] = dep[u] + 1;
            vv[v] = 1;
            q.push(v);
        }
    }
}
int main(){
    int n, m;
    scanf("%d%d", &n, &m);
    int a, b;
    memset(head, -1, sizeof(head));
    for(int i = 2; i <= n; i ++){
        scanf("%d", &a);
        add_edge(a, i);
        add_edge(i, a);
    }
    cnt = 0;
    bfs();
    dfs(1);
    RMQ(2*n);
    while(m --){
        scanf("%d%d", &a, &b);
        int lc = solve(a, b);
        if(lc == a)
            printf("%d %d\n", rmq[P[lc]], rmq[P[b]] - rmq[P[lc]]);
        else if(lc == b){
            printf("%d %d\n", rmq[P[a]] - rmq[P[lc]], rmq[P[lc]]);
        }else {
            printf("%d %d\n", rmq[P[a]], rmq[P[b]] - rmq[P[lc]]);
        }
    }
    return 0;
}
/*
6 1
4 1 1 3 3
5 6
*/