bzoj2683: 简单题

CDQ分治，然而超过内存了

CDQ分治的思想还是很有趣的。

http://www.lydsy.com/JudgeOnline/problem.php?id=2683

/**************************************************************
    Problem: 2683
    User: 1349367067
    Language: C++
    Result: Accepted
    Time:7344 ms
    Memory:45028 kb
****************************************************************/

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#define N 800011
using namespace std;
int n;
struct Node
{
       int x,y,belong,opt,no,a;
}q[N],nq[N];
int num=0,T=0;
bool cmp(Node a,Node b)
{
     if (a.x==b.x&&a.y==b.y) return a.opt<b.opt;
     if (a.x==b.x) return a.y<b.y;
     return a.x<b.x;
}
int c[N];
inline int lowbit(int x) {return x&(-x);}
int getsum(int x)
{
    int ret=0;
    while (x)
    {ret+=c[x];x-=lowbit(x);}
    return ret;
}
void update(int x,int a)
{
     while (x<=n)
     {c[x]+=a;x+=lowbit(x);}
}
int ans[N]={};
void sov(int l,int r)
{
     if (l==r) return;
     int mid=(l+r)/2,l1,l2;
     for (int i=l;i<=r;i++)
     {
         if (q[i].no<=mid&&q[i].opt==1) update(q[i].y,q[i].a);
         if (q[i].no>mid&&q[i].opt==2) ans[q[i].belong]+=q[i].a*getsum(q[i].y);
     }
     for (int i=l;i<=r;i++)
     {
         if (q[i].no<=mid&&q[i].opt==1) update(q[i].y,-q[i].a);
     }
     l1=l;l2=mid+1;
     for (int i=l;i<=r;i++)
     {
         if (q[i].no<=mid) nq[l1++]=q[i];
         else nq[l2++]=q[i];
     }
     for (int i=l;i<=r;i++)
         q[i]=nq[i];
     sov(l,mid);sov(mid+1,r);
}

int main()
{
    scanf("%d",&n);
    int tem;
    while (scanf("%d",&tem),tem!=3)
    {
          if (tem==1)
          {
             int x,y,a;scanf("%d%d%d",&x,&y,&a);
             num++;
             q[num].opt=tem;
             q[num].x=x;q[num].y=y;q[num].a=a;
             q[num].no=num;
          }
          else
          {
              int x1,y1,x2,y2;
              scanf("%d%d%d%d",&x1,&y1,&x2,&y2);
              q[++num].opt=tem;q[num].x=x1-1;q[num].y=y1-1;q[num].a=1;q[num].no=num;q[num].belong=++T;
              q[++num].opt=tem;q[num].x=x1-1;q[num].y=y2;q[num].a=-1;q[num].no=num;q[num].belong=T;
              q[++num].opt=tem;q[num].x=x2;q[num].y=y1-1;q[num].a=-1;q[num].no=num;q[num].belong=T;
              q[++num].opt=tem;q[num].x=x2;q[num].y=y2;q[num].a=1;q[num].no=num;q[num].belong=T;
          }
    }

    sort(q+1,q+num+1,cmp);
    sov(1,num);
    for (int i=1;i<=T;i++)
        printf("%d\n",ans[i]);

    return 0;
}