二分搜索 POJ 3258 River Hopscotch

题目传送门

 1 /*
 2     二分：搜索距离，判断时距离小于d的石头拿掉
 3 */
 4 #include <cstdio>
 5 #include <algorithm>
 6 #include <cstring>
 7 #include <cmath>
 8 using namespace std;
 9
10 typedef long long ll;
11 const int MAXN = 5e4 + 10;
12 const int INF = 0x3f3f3f3f;
13 ll a[MAXN];
14 int n, m;
15
16 bool check(ll d)    {
17     int last = 0;  int cnt = 0;
18     for (int i=1; i<=n+1; ++i)  {
19         if (a[i] - a[last] <= d)    cnt++;
20         else    last = i;
21     }
22     return cnt > m;
23 }
24
25 int main(void)  {       //POJ 3258 River Hopscotch
26     //freopen ("POJ_3258.in", "r", stdin);
27
28     ll x;
29     while (scanf ("%I64d%d%d", &x, &n, &m) == 3)    {
30         a[0] = 0;   a[n+1] = x;
31         for (int i=1; i<=n; ++i)    {
32             scanf ("%I64d", &a[i]);
33         }
34
35         sort (a, a+n+2);    ll l = 0, r = a[n+1];
36         while (l <= r)   {
37             ll mid = (l + r) >> 1;
38             if (check (mid))    r = mid - 1;
39             else    l = mid + 1;
40         }
41         printf ("%I64d\n", l);
42     }
43
44     return 0;
45 }