Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100"
.
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public class Solution { public String addBinary(String a, String b) { if (a == null || a.length() == 0) { return b; } if (b == null || b.length() == 0) { return a; } int addBits = Math.min(a.length(), b.length()); StringBuffer sb = new StringBuffer(); int bitPlus = 0; for (int i = 0; i < addBits; i++) { int aBit = a.charAt(a.length() - 1 - i) - '0'; int bBit = b.charAt(b.length() - 1 - i) - '0'; int cur = aBit + bBit + bitPlus; bitPlus = cur / 2; cur = cur % 2; sb.insert(0, String.valueOf(cur)); } return doOther( a, b, addBits, bitPlus, sb); } public String doOther(String a, String b, int addBits,int bitPlus,StringBuffer sb) { if (b.length() > a.length()) { doOther( b, a, addBits, bitPlus, sb); } else { for (int i = addBits; i < a.length();i++) { int aBit = a.charAt(a.length() - 1 - i ) - '0'; int cur = aBit + bitPlus; bitPlus = cur / 2; cur = cur % 2; sb.insert(0,String.valueOf(cur)); } if (bitPlus == 1) { sb.insert(0,"1"); } return sb.toString(); } return sb.toString(); } }
时间: 2024-10-24 22:00:35