1. 题目描述
有m个时间段，每个时间段效率为efficiency，每个时间段过后需要休息r时间，求最大效率和（时间段不重叠）。
2. 代码示例
1 /*
2 Source Code
3
4 Problem: 3616 User: robinho364
5 Memory: 180K Time: 0MS
6 Language: C++ Result: Accepted
7 */
8 #define _USE_MATH_DEFINES
9
10 #ifdef ONLINE_JUDGE
11 #define FINPUT(file) 0
12 #define FOUTPUT(file) 0
13 #else
14 #define FINPUT(file) freopen(file,"r",stdin)
15 #define FOUTPUT(file) freopen(file,"w",stdout)
16 #endif
17
18 #include <iostream>
19 #include <cstdio>
20 #include <cstring>
21 #include <cstdlib>
22 #include <cmath>
23 #include <ctime>
24 #include <set>
25 #include <stack>
26 #include <string>
27 #include <map>
28 #include <vector>
29 #include <queue>
30 #include <algorithm>
31 #include <functional>
32
33 typedef long long ll;
34 static const int M = 1010;
35 static const int N = 1000010;
36 static const int LEN = 1000010;
37 static const int MAX = 0x7fffffff;
38 static const int MIN = ~MAX;
39 static const double EPS = 1e-7;
40
41 struct cow_t {
42 int start;
43 int end;
44 int efficiency;
45
46 bool operator < (const struct cow_t& t) const {
47 if (end < t.end) {
48 return true;
49 }
50 else {
51 return false;
52 }
53 }
54 }cows[M];
55
56 void solve(int n, int m, int r)
57 {
58 for (int i = 0; i < m; i++) {
59 scanf("%d%d%d", &cows[i].start, &cows[i].end, &cows[i].efficiency);
60 }
61
62 std::sort(cows, cows + m);
63
64 int pos[M];
65
66 for (int i = 0; i < m; i++) {
67 int idx = i - 1;
68 while (idx >= 0) {
69 if (cows[idx].end + r <= cows[i].start) {
70 pos[i] = idx;
71 break;
72 }
73 idx--;
74 }
75 if (idx == -1) {
76 pos[i] = -1;
77 }
78 }
79
80 int dp[M];
81 memset(dp, 0, sizeof(dp));
82
83 for (int i = 0; i < m; i++) {
84 if (pos[i] == -1) {
85 dp[i] = std::max(cows[i].efficiency, dp[i - 1]);
86 }
87 else {
88 dp[i] = std::max(dp[pos[i]] + cows[i].efficiency, dp[i - 1]);
89 }
90 }
91
92 printf("%d\n", dp[m - 1]);
93 }
94
95 int main()
96 {
97 FINPUT("in.txt");
98 FOUTPUT("out.txt");
99
100 int n, m, r;
101 while (scanf("%d%d%d", &n, &m, &r) != EOF) {
102 solve(n, m, r);
103 }
104 return 0;
105 }
source code
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时间： 2024-12-30 00:00:22