Java学习之多线程同步 <好程序员特训营>

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要求：用两个线程分别输出0到100之间的奇数和偶数，要求先输出10个奇数，再输出10个偶数，再输出10个奇数，以此类推

//Print类
public class Print {
	public void odd(int i){
		System.out.println(Thread.currentThread().getName() + "输出：" + i);
	}
	public void even(int i){
		System.out.println(Thread.currentThread().getName() + "输出：" + i);
	}
}

//PrintOdd.java
public class PrintOdd extends Thread {
	private Print p;

	public PrintOdd(Print p) {
		this.p = p;
	}

	public void run() {
		int count = 0;//控制循环次数(10次循环后等待)
		for (int i = 0; i < 100; i += 2) {
			synchronized (p) {
				p.odd(i);
				count++;
				if (count == 10) {
					count = 0;
					try {
						p.wait();//输出10个数后该线程等待
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
				p.notifyAll();//唤醒其他线程
			}
		}
	}
}

//PrintEven.java
public class PrintEven extends Thread {
	private Print p;
	public PrintEven(Print p) {
		this.p = p;
	}

	public void run(){
		int count = 0;
		for (int i = 1; i < 100; i += 2) {
			synchronized (p) {
				p.even(i);
				count++;
				if (count == 10) {
					count = 0;
					try {
						p.wait();
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
				p.notifyAll();
			}
		}
	}
}

//TestDemo.java
public class TestDemo {
	public static void main(String[] args) {
		Print p = new Print();
		new PrintEven(p).start();
		new PrintOdd(p).start();
	}
}