Given a string, your task is to count how many palindromic substrings in this string.
The substrings with different start indexes or end indexes are counted as different substrings even they consist of same characters.
Example 1:
Input: "abc" Output: 3 Explanation: Three palindromic strings: "a", "b", "c".
Example 2:
Input: "aaa" Output: 6 Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".
Note:
- The input string length won‘t exceed 1000.
给定一个字符串，你的任务是计算这个字符串中有多少个回文子串。
具有不同开始位置或结束位置的子串，即使是由相同的字符组成，也会被计为是不同的子串。
示例 1:
输入: "abc" 输出: 3 解释: 三个回文子串: "a", "b", "c".
示例 2:
输入: "aaa" 输出: 6 说明: 6个回文子串: "a", "a", "a", "aa", "aa", "aaa".
注意:
- 输入的字符串长度不会超过1000。
16ms
1 class Solution {
2 func countSubstrings(_ s: String) -> Int {
3 var count = 0
4 var s = Array(s)
5 for i in 0..<s.count {
6 if i + 1 < s.count, s[i] == s[i + 1] {
7 count += numPalindromes(s, i, i + 1)
8 }
9 count += numPalindromes(s, i, i)
10 }
11 return count
12 }
13
14 func numPalindromes(_ s: [Character], _ i: Int, _ j: Int) -> Int {
15 var count = 0, i = i, j = j
16 while i >= 0, j < s.count, s[i] == s[j] {
17 i -= 1
18 j += 1
19 count += 1
20 }
21 return count
22 }
23 }
20ms
1 class Solution {
2 func countSubstrings(_ s: String) -> Int {
3 var result = 0
4 let input = Array(s)
5 for i in 0..<input.count {
6 checkPalindrom(i,i,input,&result)
7 checkPalindrom(i,i + 1,input,&result)
8 }
9 return result
10 }
11
12 func checkPalindrom(_ left: Int, _ right: Int, _ input: [Character], _ result: inout Int) {
13 let count = input.count
14 var i = left, j = right
15 while i >= 0, j < count {
16 if input[i] == input[j] {
17 result += 1
18 i -= 1
19 j += 1
20 }else{
21 break
22 }
23 }
24 }
25 }
28ms
1 class Solution {
2 func countSubstrings(_ s: String) -> Int {
3 let arr = Array(s)
4 let cnt = s.count
5 if cnt == 0 {
6 return 0
7 }
8 var result = 0
9
10 for center in 0..<cnt {
11 var left = center
12 var right = center
13
14 while left >= 0 && right < cnt && arr[left] == arr[right] {
15 result += 1
16 left -= 1
17 right += 1
18 }
19 }
20
21 for center in 1..<cnt {
22 var left = center-1
23 var right = center
24
25 while left >= 0 && right < cnt && arr[left] == arr[right] {
26 result += 1
27 left -= 1
28 right += 1
29 }
30 }
31 return result
32 }
33 }
32ms
1 class Solution {
2 func countSubstrings(_ s: String) -> Int {
3 let s = Array(s)
4 var n = s.count, ans = 0
5 for center in 0..<2*n {
6 var left = center / 2
7 var right = left + center % 2
8 while (left >= 0 && right < n &&
9 s[s.index(s.startIndex,offsetBy:left)] ==
10 s[s.index(s.startIndex,offsetBy:right)]) {
11 ans+=1
12 left-=1
13 right+=1
14 }
15 }
16 return ans
17 }
18 }
40ms
1 class Solution {
2 func countSubstrings(_ s: String) -> Int {
3 let chars = Array(s)
4 func extend(_ left: Int, _ right: Int) -> Int {
5 var (left, right) = (left, right)
6 var count = 0
7 while left >= 0
8 && right < chars.count
9 && chars[left] == chars[right] {
10 left -= 1
11 right += 1
12 count += 1
13 }
14
15 return count
16 }
17
18 return chars.indices.map {
19 extend($0, $0) + extend($0, $0 + 1)
20 }
21 .reduce(0, +)
22 }
23 }
56ms
1 class Solution {
2 func countSubstrings(_ s: String) -> Int {
3 guard s.count > 1 else{
4 return 1
5 }
6
7 var manipulationStr : [Character] = []
8 for char in Array(s){
9 manipulationStr.append("#")
10 manipulationStr.append(char)
11 }
12 manipulationStr.append("#")
13
14 var count : Int = 0
15 for movingIndex in 1..<manipulationStr.count - 1{
16 var leftIndex = movingIndex
17 var rightIndex = movingIndex
18 while leftIndex >= 0 && rightIndex < manipulationStr.count{
19 if manipulationStr[leftIndex] != manipulationStr[rightIndex]{
20 break
21 }else{
22 if manipulationStr[leftIndex] != "#"{
23 count += 1
24 }
25 leftIndex -= 1
26 rightIndex += 1
27 }
28 }
29 }
30 return count
31 }
32 }
原文地址：https://www.cnblogs.com/strengthen/p/10482491.html
时间： 2024-08-16 16:34:35