循环-07. 爬动的蠕虫(15)

 1 #include<iostream>
 2 using namespace std;
 3 int u,d;
 4 int sum(int t){
 5     if(t%2==0)
 6         return (u-d)*t/2;
 7     else
 8         return u*(t/2+1)-d*t/2;
 9 }
10 int main(){
11     int t,n;
12     cin>>n>>u>>d;
13     for(t=1;sum(t)<n;)
14         t++;
15     cout<<t<<endl;
16     return 0;
17 }

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