摘自:http://shine-it.net/index.php?topic=14575.0
def _rmb_upper(self, value): """ 人民币大写 来自:http://topic.csdn.net/u/20091129/20/b778a93d-9f8f-4829-9297-d05b08a23f80.html 传入浮点类型的值返回 unicode 字符串 """ map = [u"零",u"壹",u"贰",u"叁",u"肆",u"伍",u"陆",u"柒",u"捌",u"玖"] unit = [u"分",u"角",u"元",u"拾",u"百",u"千",u"万",u"拾",u"百",u"千",u"亿", u"拾",u"百",u"千",u"万",u"拾",u"百",u"千",u"兆"] nums = [] #取出每一位数字,整数用字符方式转换避大数出现误差 for i in range(len(unit)-3, -3, -1): if value >= 10**i or i < 1: nums.append(int(round(value/(10**i),2))%10) words = [] zflag = 0 #标记连续0次数,以删除万字,或适时插入零字 start = len(nums)-3 for i in range(start, -3, -1): #使i对应实际位数,负数为角分 if 0 != nums[start-i] or len(words) == 0: if zflag: words.append(map[0]) zflag = 0 words.append(map[nums[start-i]]) words.append(unit[i+2]) elif 0 == i or (0 == i%4 and zflag < 3): #控制‘万/元’ words.append(unit[i+2]) zflag = 0 else: zflag += 1 if words[-1] != unit[0]: #结尾非‘分’补整字 words.append(u"整") return ‘‘.join(words)
时间: 2024-11-03 02:56:01