∂ t r ( B A − 1 ) ∂ A = − ( A − 1 B T A − 1 ) T {\displaystyle {\frac {\partial \mathrm {tr} (\mathbf {B} \mathbf {A} ^{-1})}{\partial \mathbf {A} }}=-(\mathbf {A} ^{-1}\mathbf {B} ^{T}\mathbf {A} ^{-1})^{T}}
时间: 2024-10-05 23:09:14
∂ t r ( B A − 1 ) ∂ A = − ( A − 1 B T A − 1 ) T {\displaystyle {\frac {\partial \mathrm {tr} (\mathbf {B} \mathbf {A} ^{-1})}{\partial \mathbf {A} }}=-(\mathbf {A} ^{-1}\mathbf {B} ^{T}\mathbf {A} ^{-1})^{T}}