注意n=1的情况
#include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <climits> #include <string> #include <iostream> #include <map> #include <cstdlib> #include <list> #include <set> #include <queue> #include <stack> using namespace std; typedef unsigned long long LL; LL n,a,b,r; LL mypow(LL a,LL b) { if(b == 0) return 1; a %= r; if(b & 1) return mypow(a * a % r,b / 2) % r * a % r; else return mypow(a * a % r,b / 2) % r; } void solve() { LL now = 1,prev = 0,round = 1; while(1) { LL tmp = now; now = now + prev; prev = tmp; now %= n; prev %= n; if(round != 1 && now == 1 % n && prev == 0) break; round++; } r = round; LL t = mypow(a,b); if(t == 0) cout << 0 << endl; else if(t == 1) cout << 1 % n << endl; else { prev = 1; now = 0; for(int i = 1;i <= t;i++) { LL tmp = now; now += prev; now %= n; prev = tmp; } cout << now % n << endl; } } int main() { int T; cin >> T; while(T--) { cin >> a >> b >> n; solve(); } return 0; }
UVA 11582 Colossal Fibonacci Numbers! 找循环节
时间: 2024-10-15 04:35:02