D - Charm Bracelet 背包问题

Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u

Submit Status Practice POJ 3624

Description

Bessie has gone to the mall‘s jewelry store and spies a charm bracelet. Of course, she‘d like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight W_i (1 ≤ W_i ≤ 400), a ‘desirability‘ factor D_i (1 ≤ D_i ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

Input

* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: W_i and D_i

Output

* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

Sample Input

4 6
1 4
2 6
3 12
2 7

Sample Output

23

 1 Home    Problems    Status    Contest    [xiong_tao]    Logout
 2 xiong_tao ‘s source code for D
 3 Memory: 1952 KB         Time: 313 MS
 4 Language: G++         Result: Accepted
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28 #include<cstdio>
29 #include<string.h>
30 using namespace std;
31 int dp[400000],w[400000],d[4000];
32 int n,m;
33 int main()
34 {
35     int i,j;
36     while(scanf("%d%d",&n,&m)!=EOF)
37     {
38         for(i=0;i<n;i++)
39             scanf("%d%d",&w[i],&d[i]);
40         memset(dp,0,sizeof(dp));
41         for(i=0;i<n;i++)
42             for(j=m;j>=0;j--)
43                if(j>=w[i])
44                dp[j]=dp[j]>dp[j-w[i]]+d[i]?dp[j]:dp[j-w[i]]+d[i];
45         printf("%d\n",dp[m]);
46     }
47     return 0;
48 }
49
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53 Server Time: 2014-07-28 18:43:07

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