这个示例中BoundedBuffer是一个固定长度的集合,这个在其put操作时,如果发现长度已经达到最大长度,那么会等待notFull信号,如果得到notFull信号会像集合中添加元素,并发出notEmpty的信号,而在其take方法中如果发现集合长度为空,那么会等待notEmpty的信号,同时如果拿到一个元素,那么会发出notFull的信号。
package locks; import java.util.Random; import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock; public class AppOfficial { /** * BoundedBuffer 是一个定长100的集合,当集合中没有元素时,take方法需要等待,直到有元素时才返回元素 * 当其中的元素数达到最大值时,要等待直到元素被take之后才执行put的操作 * @author yukaizhao * */ static class BoundedBuffer { final Lock lock = new ReentrantLock(); final Condition notFull = lock.newCondition(); final Condition notEmpty = lock.newCondition(); final Object[] items = new Object[100]; int putptr, takeptr, count; public void put(Object x) throws InterruptedException { System .out.println("put wait lock"); lock.lock(); System.out.println("put get lock"); try { while (count == items.length) { System.out.println("buffer full, please wait"); notFull.await(); } items[putptr] = x; if (++putptr == items.length) putptr = 0; ++count; notEmpty.signal(); } finally { lock.unlock(); } } public Object take() throws InterruptedException { System.out.println("take wait lock"); lock.lock(); System.out.println("take get lock"); try { while (count == 0) { System.out.println("no elements, please wait"); notEmpty.await(); } Object x = items[takeptr]; if (++takeptr == items.length) takeptr = 0; --count; notFull.signal(); return x; } finally { lock.unlock(); } } } public static void main(String[] args) { final BoundedBuffer boundedBuffer = new BoundedBuffer(); Thread t1 = new Thread(new Runnable() { @Override public void run() { System.out.println("t1 run"); for (int i=0;i<1000;i++) { try { System.out.println("putting.."); boundedBuffer.put(Integer.valueOf(i)); } catch (InterruptedException e) { e.printStackTrace(); } } } }) ; Thread t2 = new Thread(new Runnable() { @Override public void run() { for (int i=0;i<1000;i++) { try { Object val = boundedBuffer.take(); System.out.println(val); } catch (InterruptedException e) { e.printStackTrace(); } } } }) ; t1.start(); t2.start(); } }
时间: 2024-10-18 12:39:57