思路:
//By SiriusRen #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; const int mod=1000000007; int cases,n,maxval,a[44][44],C[44][44],f[44],val[44],X,g[44]; int top2,top,bgn,half,cnts2[22],allnum[44],Ans,T; struct Node{int wei,num;Node(){}Node(int x,int y){wei=x,num=y;}}s[5+(1<<20)],s2[5+(1<<20)]; bool operator<(Node a,Node b){return a.wei<b.wei;} int pow(ll x,int y){ ll res=1; while(y){ if(y&1)res=res*x%mod; x=x*x%mod,y>>=1; }return (int)res; } int Gauss(int n){ int f=1; for(int i=1;i<=n;i++){ int j=i;while(!a[i][j]&&j<=n)j++; if(j==n+1)return 0; if(j!=i){ for(int k=1;k<=n;k++)swap(a[i][k],a[j][k]); f*=-1; } int t=pow(a[i][i],mod-2); for(int j=i+1;j<=n;j++){ int ww=1ll*a[j][i]*t%mod; for(int k=i;k<=n;k++)a[j][k]=(a[j][k]-1ll*ww*a[i][k]%mod+mod)%mod; } } ll ans=1; for(int i=1;i<=n;i++)ans=ans*a[i][i]%mod; if(f==-1)ans=(mod-ans)%mod; return ans; } void Kirchhoff(int x){ memset(a,0,sizeof(a)); for(int i=1;i<=n;i++) if(i<=x)for(int j=max(i+1,X+1);j<=n;j++)a[i][j]--,a[j][i]--,a[i][i]++,a[j][j]++; else for(int j=i+1;j<=n;j++)a[i][j]--,a[j][i]--,a[i][i]++,a[j][j]++; } bool cmp(int x,int y){return x>y;} void dfs(int x,int wei,int deep){ !T?s[top++]=Node(wei,deep):s2[top2++]=Node(wei,deep); for(int i=x;i>bgn;i--)if(wei+val[i]<=maxval)dfs(i-1,wei+val[i],deep+1); } signed main(){ for(int i=0;i<=40;i++){ C[i][0]=C[i][i]=1; for(int j=1;j<i;j++)C[i][j]=(C[i-1][j-1]+C[i-1][j])%mod; } scanf("%d",&cases); while(cases--){ memset(allnum,0,sizeof(allnum)); memset(cnts2,0,sizeof(cnts2)); top=top2=X=bgn=Ans=T=0; scanf("%d%d",&n,&maxval); for(int i=1;i<=n;i++){ scanf("%d",&val[i]); if(~val[i])X++; }half=(X+1)/2; for(int i=0;i<=X;i++)Kirchhoff(i),f[i]=g[i]=Gauss(n-1); for(int i=X;~i;i--) for(int j=i+1;j<=X;j++)f[i]=((f[i]-1ll*C[X-i][j-i]*f[j])%mod+mod)%mod; sort(val+1,val+1+n,cmp),random_shuffle(val+1,val+1+X); dfs(half,0,0),sort(s,s+top); T=1,bgn=half,dfs(X,0,0),sort(s2,s2+top2); for(int i=0;i<top2;i++)cnts2[s2[i].num]++; for(int i=0,j=top2-1;i<top;i++){ while(s[i].wei+s2[j].wei>maxval)cnts2[s2[j].num]--,j--; for(int k=0;k<=X-half;k++)(allnum[k+s[i].num]+=cnts2[k])%=mod; } for(int i=0;i<=X;i++)Ans=(Ans+1ll*f[X-i]*allnum[i])%mod; printf("%d\n",(Ans+mod)%mod); } }
时间: 2024-10-22 19:45:44