Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
You are given a target value to search. If found in the array return its index, otherwise return -1.
You may assume no duplicate exists in the array.
Solution:
class Solution { public: int search(vector<int>& nums, int target) { for(int i=0;i<nums.size();i++){ if(nums[i]==target){ return i; } } return -1; } };
时间: 2024-11-06 07:34:18