获取两个字符串所有公共的子串算法

应用场景： 获取两个字符串所有公共的子串。

思路： 1. 先获取两个子串的交集

2. 遍历交集子串，从最短子串到最长子串

public static List<String> getAllCommonSubStrings(String str1, String str2) {
        //TODO null check.

        String longString = str1;
        String shortString = str2;
        if(str1.length() < str2.length()){
            longString = str2;
            shortString = str1;
        }

        List<String> result = new ArrayList<String>();
        List<String> vacancy = new ArrayList<String>();
        vacancy.add("");

        List<String> list1 = Arrays.asList(shortString.split(""));
        List<String> list2 = Arrays.asList(longString.split(""));

        result.addAll(list1);
        result.retainAll(list2);
        result.removeAll(vacancy);

        List<String> commonSubStrings = new ArrayList<String>();
        StringBuffer strBuf = new StringBuffer();

        for(int i = 0; i < result.size()-1; i++){
            strBuf = strBuf.append(result.get(i));
            if(shortString.contains(strBuf + result.get(i+1))
                    && longString.contains(strBuf + result.get(i+1))
                    && i < result.size()-2){
                continue;
            }else{
               commonSubStrings.add(strBuf.toString());
               strBuf = new StringBuffer();
            }
        }
        String tail = commonSubStrings.get(commonSubStrings.size()-1)+ result.get(result.size()-1);
        if(shortString.contains(tail)
                && longString.contains(tail)){
            commonSubStrings.set(commonSubStrings.size()-1, tail);
        }else{
            commonSubStrings.add(result.get(result.size()-1));
        }

        return commonSubStrings;
    }

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