LeetCode139:Word Break

Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

思路：dp[i]=dp[j]+s.contais(s.substring(j,i+1));

 1 public class Solution {
 2     public boolean wordBreak(String s, Set<String> wordDict) {
 3
 4         int m=s.length();
 5         boolean isSegmented[]=new boolean[m+1];
 6         isSegmented[0]=true;
 7         int start=0;
 8         for(int i=0;i<m;i++)
 9         for(int j=0;j<=i;j++){
10            isSegmented[i+1]=isSegmented[j]&&wordDict.contains(s.substring(j,i+1));
11            if(isSegmented[i+1])
12            break;
13         }
14         return isSegmented[m];
15     }
16
17 }

时间： 2024-10-15 17:49:48

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