Move Zeroes——Leetcode

Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

1. You must do this in-place without making a copy of the array.
2. Minimize the total number of operations.

题目大意：给定一个数组，把所有的0放到数组后面，所有的非0元素放到前面，并且保证非0元素顺序不变。

解题思路，从前往后遍历，遇见0则cnt++，遇见非0则往前移cnt个，最后把后cnt个设置为0就可以了。

    public void moveZeroes(int[] nums) {
        if(nums==null||nums.length==0){
            return;
        }
        int cnt = 0;
        for(int i=0;i<nums.length;i++){
            if(nums[i]==0){
                cnt++;
            }else{
                nums[i-cnt]=nums[i];
            }
        }
        if(cnt>0){
            Arrays.fill(nums,nums.length-cnt,nums.length,0);
        }
    }