[PAT] 1081 Rational Sum （20 分）Java

Given N rational numbers in the form numerator/denominator, you are supposed to calculate their sum.

Input Specification:

Each input file contains one test case. Each case starts with a positive integer N (≤100), followed in the next line N rational numbers a1/b1 a2/b2 ... where all the numerators and denominators are in the range of long int. If there is a negative number, then the sign must appear in front of the numerator.

Output Specification:

For each test case, output the sum in the simplest form integer numerator/denominator where integer is the integer part of the sum, numerator < denominator, and the numerator and the denominator have no common factor. You must output only the fractional part if the integer part is 0.

Sample Input 1:

5
2/5 4/15 1/30 -2/60 8/3

Sample Output 1:

3 1/3

Sample Input 2:

2
4/3 2/3

Sample Output 2:

2

Sample Input 3:

3
1/3 -1/6 1/8

Sample Output 3:

7/24

 1 package pattest;
 2
 3 import java.io.BufferedReader;
 4 import java.io.IOException;
 5 import java.io.InputStreamReader;
 6
 7 /**
 8  * @Auther: Xingzheng Wang
 9  * @Date: 2019/2/26 21:26
10  * @Description: pattest
11  * @Version: 1.0
12  */
13 public class PAT1081 {
14     public static void main(String[] args) throws IOException {
15         BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
16         String n = reader.readLine();
17         String[] s1 = reader.readLine().split(" ");
18         String[] s2 = s1[0].split("/");
19         int a = Integer.parseInt(s2[0]), b = Integer.parseInt(s2[1]), sum = 0;
20         for (int i = 1; i < Integer.parseInt(n); i++) {
21             String[] s = s1[i].split("/");
22             int atemp = Integer.parseInt(s[0]);
23             int btemp = Integer.parseInt(s[1]);
24             a = a * btemp + atemp * b;
25             b = b * btemp;
26             int c = GCD(a, b);
27             a = a / c;
28             b = b / c;
29         }
30         if (a % b == 0) {
31             System.out.print(a / b);
32         } else {
33             if (Math.abs(a) > Math.abs(b)) {
34                 if (a > 0) {
35                     System.out.printf("%d %d/%d", a / b, a - a / b * b, b);
36                 } else {
37                     a = -a;
38                     System.out.printf("-%d %d/%d", a / b, a - a / b * b, b);
39                 }
40             } else {
41                 System.out.printf("%d/%d", a - a / b * b, b);
42             }
43         }
44     }
45
46     private static int GCD(int m, int n) {
47         return n == 0 ? m : GCD(n, m % n);
48     }
49 }

原文地址：https://www.cnblogs.com/PureJava/p/10498125.html