A控制器----B控制器-----C控制器：C直接跳转A

自定义C控制器返回按钮

1         UIBarButtonItem *backBarButton = [[UIBarButtonItem alloc] initWithTitle:@"返回" style:UIBarButtonItemStylePlain target:self action:@selector(back)];
2
3         self.navigationItem.leftBarButtonItem = backBarButton;

监听back

- (void)back
{
    UIViewController *popVC = self.navigationController.viewControllers[1];

    NSLog(@"%@", self.navigationController.viewControllers);

    [self.navigationController popToViewController:popVC animated:YES];

}

具体要返回到第几个控制器 可以打印

self.navigationController.viewControllers

这是数组，可以看到里面每个控制器的顺序改变索引就可以任意跳转了

注意:如果没有自定义按钮 需要实现以下方法 避免可以左滑返回:

1 - (void)viewWillAppear:(BOOL)animated
2 {
3
4     self.navigationController.interactivePopGestureRecognizer.enabled = NO;
5 }

1 - (void)viewWillDisappear:(BOOL)animated
2
3 {
4
5          self.navigationController.interactivePopGestureRecognizer.enabled = YES;
6
7 }