1.大整数加法
用数组来存储大整数的每一位,然后模拟人工运算,用for循环按位运算和处理,原理十分简单,直接上模板。
#include<iostream> #include<vector> using namespace std; //大整数加法 vector<int> add(vector<int>& A,vector<int>& B){ vector<int> C; int t = 0; for(int i = 0; i < A.size() || i < B.size();i++){ if( i < A.size() ) t += A[i]; if( i < B.size() ) t += B[i]; C.push_back(t%10); t /= 10; } if(t) C.push_back(1); return C; } int main(){ string a,b; vector<int>A,B; cin>>a>>b; for(int i = a.size()-1;i>=0;i--) A.push_back(a[i]-‘0‘); for(int i = b.size()-1;i>=0;i--) B.push_back(b[i]-‘0‘); auto C = add(A,B); for(int i = C.size()-1;i>=0;i--) cout<<C[i]; cout<<endl; return 0; }
2.大整数减法
#include<iostream> #include<vector> using namespace std; //判断A是否大于等于B bool cmp(vector<int>& A,vector<int>& B){ if( A.size() != B.size() ) return A.size() > B.size(); for(int i = A.size() - 1;i >= 0; i -- ){ if( A[i] != B[i] ) return A[i] > B[i]; } return 1; } //C = A - B vector<int> sub(vector<int>& A,vector<int>& B){ vector<int> C; for(int i = 0,t = 0 ;i <= A.size(); i ++){ t = A[i]-t; if(i < B.size() ) t -= B[i]; C.push_back( (t + 10) % 10 ); if(t < 0){t = 1;} else t = 0; } while(C.size() > 1 && C.back() == 0) C.pop_back(); return C; } //C = A + B vector<int> add(vector<int>& A,vector<int>& B){ vector<int> C; int t = 0; for(int i = 0; i < A.size() || i < B.size();i++){ if( i < A.size() ) t += A[i]; if( i < B.size() ) t += B[i]; C.push_back(t%10); t /= 10; } if(t) C.push_back(1); return C; } int main(){ string a,b; vector<int>A,B; cin>>a>>b; for(int i = a.size()-1;i>=0;i--) A.push_back(a[i]-‘0‘); for(int i = b.size()-1;i>=0;i--) B.push_back(b[i]-‘0‘); if(cmp(A,B)){ auto C = sub(A,B); for(int i = C.size()-1;i>=0;i--) cout<<C[i]; cout<<endl; }else{ auto C = sub(B,A); cout<<"-"; for(int i = C.size()-1;i>=0;i--) cout<<C[i]; cout<<endl; } return 0; }
3.大整数乘法
#include <iostream> #include <vector> using namespace std; vector<int> mul(vector<int> A, vector<int> B) { vector<int> C(A.size() + B.size()); for (int i = 0; i < A.size(); i ++ ) for (int j = 0; j < B.size(); j ++ ) C[i + j] += A[i] * B[j]; for (int i = 0, t = 0; i < C.size() || t; i ++ ) { t += C[i]; if (i >= C.size()) C.push_back(t % 10); else C[i] = t % 10; t /= 10; } while (C.size() > 1 && !C.back()) C.pop_back(); return C; } int main() { string a, b; cin >> a >> b; vector<int> A, B; for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - ‘0‘); for (int i = b.size() - 1; i >= 0; i -- ) B.push_back(b[i] - ‘0‘); auto C = mul(A, B); for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i]; cout << endl; return 0; }
4.大整数除法
#include <iostream> #include <vector> #include <algorithm> using namespace std; vector<int> div(vector<int> &A, int b, int &r) { vector<int> C; r = 0; for (int i = A.size() - 1; i >= 0; i -- ) { r = r * 10 + A[i]; C.push_back(r / b); r %= b; } reverse(C.begin(), C.end()); while (C.size() > 1 && C.back() == 0) C.pop_back(); return C; } int main() { string a; vector<int> A; int B; cin >> a >> B; for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - ‘0‘); int r; auto C = div(A, B, r); for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i]; cout << endl << r << endl; return 0; }
原文地址:https://www.cnblogs.com/Flydoggie/p/12235396.html
时间: 2024-10-10 04:40:13