C++中,引用const对象时,也只能通过该对象访问其const函数,因为非const函数可能修改const对象本身,编译器避免了这一类情况会报错如下:
passing ‘const Sales_data‘ as ‘this‘ argument of ‘std::string Sales_data::isbn()‘ discards qualifiers [-fpermissive]
源代码:
class Sales_data{ friend bool compareIsbn(const Sales_data &lhs,const Sales_data &rhs); string bnum; string bname; public: Sales_data(string bnum,string bname):bnum(bnum),bname(bname){} string isbn() { return this->bnum; } }; bool compareIsbn(const Sales_data &lhs,const Sales_data &rhs){ return lhs.isbn()<rhs.isbn(); }
conpareIsbn因为调用的是const对象,访问它的isbn()函数也必须是const的才能够编译通过
class Sales_data{ friend bool compareIsbn(const Sales_data &lhs,const Sales_data &rhs); string bnum; string bname; public: Sales_data(string bnum,string bname):bnum(bnum),bname(bname){} string isbn() const{ return this->bnum; } }; bool compareIsbn(const Sales_data &lhs,const Sales_data &rhs){ return lhs.isbn()<rhs.isbn(); }
时间: 2024-10-21 10:38:56