编程之类 数字号码《-》单词之间的转换

<pre name="code" class="cpp">/**
数字转换成单词，

如

1,0==》空格

2==》a或b或c

7==》p或q或r或s

*/

#include<iostream>
#include<vector>
using namespace std;
typedef struct NUM_WORD_
{
	int count;
	char word[4];
}NUM_WORD;
NUM_WORD GetWord(int num)
{
	NUM_WORD m_word;
	m_word.count=0;
    int i=0;
	switch(num)
	{
	case 0:
	case 1:
		m_word.count=1;
		m_word.word[0]=' ';
		break;
	case 2:
		m_word.count=3;
		for(i=0;i<3;i++)
			m_word.word[i]='a'+i;
		break;
	case 3:
		m_word.count=3;
		for(i=0;i<3;i++)
			m_word.word[i]='d'+i;
		break;
	case 4:
		m_word.count=3;
		for(i=0;i<3;i++)
			m_word.word[i]='g'+i;
		break;
	case 5:
		m_word.count=3;
		for(i=0;i<3;i++)
			m_word.word[i]='j'+i;
		break;
	case 6:
		m_word.count=3;
		for(i=0;i<3;i++)
			m_word.word[i]='m'+i;
		break;
	case 7:
		m_word.count=4;
		for(i=0;i<4;i++)
			m_word.word[i]='p'+i;
		break;
	case 8:
		m_word.count=3;
		for(i=0;i<3;i++)
			m_word.word[i]='t'+i;
		break;
	case 9:
		m_word.count=4;
		for(i=0;i<4;i++)
			m_word.word[i]='w'+i;
		break;
	}
	return m_word;
}
void GetValue(char*numStr,int pos,char* wordStr)
{

	if(pos>=strlen(numStr))
	{
		wordStr[pos]='\0';
		cout<<wordStr<<endl;
		return;
	}else{
        	NUM_WORD m1;
	        int num=(int)(numStr[pos]-'0');
 	        m1=GetWord(num);
	        int i=0;
	        for(i=0;i<m1.count;i++)
			{
		       wordStr[pos]=m1.word[i];
		       GetValue(numStr,pos+1,wordStr);
			}
	}
}
void Output(char*numStr)
{
	int pos=0;
	char*wordStr=new char[strlen(numStr)+1];

	GetValue(numStr,pos,wordStr);

	if(wordStr!=NULL)delete []wordStr;
}

int main()
{
	char*numStr="27";
    Output(numStr);
	return 0;
}

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