Hdu_4619 Warm up 2 -最大独立集

题意：横多米诺和竖多米诺不相交最多有多少个

/************************************************
Author        :DarkTong
Created Time  :2016/8/1 21:45:12
File Name     :Hdu_4619.cpp
*************************************************/

#include <bits/stdc++.h>
using namespace std;
const int maxn = 1000 + 10;
vector<int> w[maxn];
int n, m;
int Left[maxn];
bool used[maxn];
bool match(int i)
{
    for(int j=0;j<w[i].size();++j) if(!used[w[i][j]])
    {
        int v = w[i][j];
        used[v] = true;
        if(!Left[v]||match(Left[v]))
        {
            Left[v] = i;
            return true;
        }
    }
    return false;
}
//返回最大匹配数
int hungary()
{
    int res=0;
    memset(Left, 0, sizeof(Left));
    for(int i=1;i<=n;++i)
    {
        memset(used, 0, sizeof(used));
        if(match(i)) res++;
    }
    return res;
}
int r[maxn][2];

int main()
{
    int T, cas=1;
    while(scanf("%d%d", &n, &m)==2&&(n+m))
    {
        for(int i=0;i<maxn;++i)w[i].clear();

        int u, v;
        for(int i=1;i<=n;++i) scanf("%d%d", &r[i][0], &r[i][1]);
        for(int i=1;i<=m;++i)
        {
            scanf("%d%d", &u, &v);
            for(int j=1;j<=n;++j)
            {
                if(r[j][0]<=u&&u<=r[j][0]+1&&v<=r[j][1]&&r[j][1]<=v+1)
                {
            //        printf("---%d %d\n", j, i);
                    w[j].push_back(i);
                }
            }
        }
        printf("%d\n", n+m-hungary());
    }

    return 0;
}