题目描述:
给出若干个线段的起始点和终止点,求这些线段某个位置重合的最大个数。
思路:
可以先按照右端点升序,对每条线段,若它右边的线段开始时间在该条线段之前,表示和该条线段重合。算出这条线段的最大重合数量,再找下一条。
代码:
package com.darrenchan; import java.util.ArrayList; import java.util.Collections; import java.util.List; public class Test{ public static int getNum(List<Line> list){ int max = Integer.MIN_VALUE; //排序 Collections.sort(list); for (int i = 0; i < list.size(); i++) { int sum = 1; for (int j = i + 1; j < list.size(); j++) { if(list.get(j).start < list.get(i).end){ sum++; } } max = Math.max(max, sum); } return max; } public static void main(String[] args) { Line line1 = new Line(0,6); Line line2 = new Line(0,5); Line line3 = new Line(0,4); List<Line> list = new ArrayList<>(); list.add(line1); list.add(line2); list.add(line3); int max = getNum(list); System.out.println(max); } } class Line implements Comparable<Line> { public int start; public int end; public Line(int start, int end){ this.start = start; this.end = end; } @Override public int compareTo(Line o) { return this.end - o.end; } }
原文地址:https://www.cnblogs.com/DarrenChan/p/9688175.html
时间: 2024-10-11 05:51:06