android中对json数据的解析，并在listview中现实，下面是数据
{"ziparea": "410100.0", "enddate": "2015-04-03 00:00:00", "ecertarea": "\u9053\u8def\u8d27\u7269\u8fd0\u8f93\u9a7e\u9a76\u5458", "ecertstate": "\u4ece\u4e1a", "begindate": "2009-04-03 18:12:30", "sex": "\u7537", "birthday": "1958-06-25 00:00:00", "result": 0, "ecertid": "4101010020009000363", "addr": "\u90d1\u5dde\u5e02\u4e2d\u539f\u533a\u4f0f\u725b\u5357\u8def\u79e6\u5cad\u5c0f\u533a4\u53f7\u697c54\u53f7", "name": "\u5b54\u7965\u6c11"}
最好先定义一个实体类（A.class）对应数据。
如果你的josn是用默认的josn格式就这样
JosnArray list=JosnArray(“你上面的josn数据”);
List<A> l=new ArrayList<A>();
A a;
for(JsonObject o：list)
{
a=new A();
a.setXXX(o.getString("这里json里面对应的建"))
a.setXXX(o.getString("这里json里面对应的建"))
l.add(a);
}
这样List<A> l里面就装好了数据了直接 A.getxxx（）就ok
首先 你的json数据还应该加个key如下
{"info":[{"ziparea": "410100.0", "enddate": "2015-04-03 00:00:00", "ecertarea": "\u9053\u8def\u8d27\u7269\u8fd0\u8f93\u9a7e\u9a76\u5458", "ecertstate": "\u4ece\u4e1a", "begindate": "2009-04-03 18:12:30", "sex": "\u7537", "birthday": "1958-06-25 00:00:00", "result": 0, "ecertid": "4101010020009000363", "addr": "\u90d1\u5dde\u5e02\u4e2d\u539f\u533a\u4f0f\u725b\u5357\u8def\u79e6\u5cad\u5c0f\u533a4\u53f7\u697c54\u53f7", "name": "\u5b54\u7965\u6c11"}]}
接着定义一个entity
比如
public class Info {
private int XX= 0;
private String XXX = null;
private int XXXX= 0;
}
接着解析
方法如下
public static List<Info> getInfos(String key, String jsonString) {
List<Info> list = new ArrayList<Info>();
try {
JSONObject jsonObject = new JSONObject(jsonString);
// 返回json的数组
JSONArray jsonArray = jsonObject.getJSONArray(key);
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject jsonObject2 = jsonArray.getJSONObject(i);
Info info = new Info();
info .setXX(jsonObject2.getInt("XX"));
info .setXXX(jsonObject2.getString("XXX"));
info .setXXX(jsonObject2.getInt("XXXX"));
list.add(info);
}
} catch (JSONException e) {
e.printStackTrace();
}
return list;
}
上面代码中key就为json数据中添加的key