1058. A+B in Hogwarts (20)

时间限制

50 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it‘s easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

 1 #include<stdio.h>
 2 #include<math.h>
 3 #include<stdlib.h>
 4 #include<string.h>
 5
 6 int main()
 7 {
 8     struct hog
 9     {
10         int g, s, k;
11     };
12     hog a, b, sum;
13     sum.g = sum.s = sum.k = 0;
14     scanf("%d.%d.%d %d.%d.%d", &a.g, &a.s, &a.k, &b.g, &b.s, &b.k);
15     if(a.k + b.k < 29)
16     {
17         sum.k = a.k + b.k;
18     }
19     else
20     {
21         sum.k = a.k + b.k - 29;
22         sum.s++;
23     }
24     if(sum.s + a.s + b.s < 17)
25     {
26         sum.s += a.s + b.s;
27     }
28     else
29     {
30         sum.s += a.s + b.s - 17;
31         sum.g++;
32     }
33     sum.g += a.g + b.g;
34     printf("%d.%d.%d\n", sum.g, sum.s, sum.k);
35     return 0;
36 }