12.输入一行字符，分别统计出其中英文字母、空格、数字和其它字符的个数

s="123 abc [email protected]# ^&*"

digit_num=0

letter_num=0

space_num=0

other_num=0

for i in s:

if i.isalpha():

letter_num+=1

elif i.isdigit():

digit_num+=1

elif i.isspace():

space_num+=1

else:

other_num+=1

print u"共有字母:",letter_num

print u"共有数字:",digit_num

print u"共有空格:",space_num

原文地址：https://www.cnblogs.com/luo25236240/p/9255421.html