Leetcode 337. 打家劫舍 III

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    struct returnData
    {
        int qu;
        int buqu;
        returnData(int _qu, int _buqu): qu(_qu), buqu(_buqu){}
    };

    returnData process(TreeNode* root)
    {
        if(root==nullptr)
        {
            return returnData(0,0);
        }

        returnData left = process(root->left);

        returnData right = process(root->right);

        //父节点取的情况下
        int qu = left.buqu + right.buqu + root->val;
        //父节点不取的情况下
        int a = left.qu+right.qu;
        int b = left.qu+right.buqu;
        int c = left.buqu+right.qu;
        int d = left.buqu+right.buqu;

        int buqu = max(max(max(a,b),c),d);

        return returnData(qu, buqu);
    }

    int rob(TreeNode* root) {
        if(root==nullptr)
            return 0;
        returnData ret = process(root);
        return max(ret.qu, ret.buqu);
    }
};

原文地址：https://www.cnblogs.com/randyniu/p/9537530.html