Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace"
is a subsequence of "abcde"
while "aec"
is not).
Example 1:
s = "abc"
, t = "ahbgdc"
Return true
.
Example 2:
s = "axc"
, t = "ahbgdc"
Return false
.
Follow up:
If there are lots of incoming S, say S1, S2, ... , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?
class Solution { public boolean isSubsequence(String s, String t) { if (s == null || s.length() == 0) { return true; } int index = 0; for (char ch : t.toCharArray()) { if (index < s.length() && s.charAt(index) == ch) { index += 1; } } return index == s.length(); } }
原文地址:https://www.cnblogs.com/xuanlu/p/11840214.html