ICPC2019 亚洲区域赛 南京站

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4804 题目大意 给你一个 \(n \times m\) 的矩形区域.你需要用 \(1 \times 1\) 和 \(1 \times 2\) 的砖块铺满这个区域,且满足如下要求: 所有的砖块可以竖着放或横着放: 砖角要放在格点上: \(1 \times 1\) 的砖不能少于 \(C\) 块也不能多于 \(D\) 块, \(1 \times 2\) 的砖没有数量限制. 有些方格在一开始就已经被填充了,

http://codeforces.com/gym/101981/attachments 题意:有n个英雄,m个敌人,k瓶药剂,给出每个英雄可以消灭的敌人的编号.每个英雄只能消灭一个敌人,但每个英雄只能消灭一个敌人.现在有药剂,英雄喝了之后可以多消灭一个敌人,但每个英雄只能喝一瓶,问最多能消灭多少个敌人. 下午在实验室队内自己开训练,和JC大佬那队一起开的,当时JC大佬他们队开的J题,没有看I题,当我们队AC之后JC大佬才看了I题,听到他们说,这题就差直接把网络流三个字写在题目里了.确实非常明显

我在集训队里面也就一般水平,这次学校史无前例的拿到了8个名额,由于大三的只有两个队伍,所以我们13及能分到名额,由于13及人数很多,组长就按照谁在oj上面a的题多就让谁去,我和tyh,sxk,doubleq幸运的在大二就有机会参加亚洲现场赛,非常激动.牡丹江赛区是我和sxk和doubleq组成rainbow战队,我们对这次区域赛其实就是去张张见识,增加大赛经验(外加公费旅游2333),可是当我们真正来到赛场的时候不知道为上面我非常渴望拿一块牌子.第一天热身赛,double迅速切下水题,我一直再弄

球队内线我也总水平,这所学校得到了前所未有的8地方,因为只有两个少年队.因此,我们13并且可以被分配到的地方,因为13和非常大的数目.据领队谁oj在之上a谁去让更多的冠军.我和tyh,sxk,doubleq运的在大二就有机会參加亚洲现场赛,非常激动.牡丹江赛区是我和sxk和doubleq组成rainbow战队,我们对这次区域赛事实上就是去张张见识,添加大赛经验(外加公费旅游2333),但是当我们真正来到赛场的时候不知道为上面我非常渴望拿一块牌子. 第一天热身赛,double迅速切下水题.我一直再

Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his

Information Entropy Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Information Theory is one of the most popular courses in Marjar University. In this course, there is an important chapter about information entropy. Entropy is t

Known Notation Time Limit: 2 Seconds      Memory Limit: 131072 KB Do you know reverse Polish notation (RPN)? It is a known notation in the area of mathematics and computer science. It is also known as postfix notation since every operator in an expre

Known Notation Time Limit: 2 Seconds      Memory Limit: 65536 KB Do you know reverse Polish notation (RPN)? It is a known notation in the area of mathematics and computer science. It is also known as postfix notation since every operator in an expres

Let L denote the number of 1s in integer D's binary representation. Given two integers S1 and S2, we call D a XHY number if S1≤L≤S2. With a given D, we would like to find the next XHY number Y, which is JUST larger than D. In other words, Y is the sm